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balandron [24]
3 years ago
13

Two standard 6-sided number cubes are rolled, a red one and a blue one. How many different sums are possible? ​

Mathematics
1 answer:
AlladinOne [14]3 years ago
8 0

Answer:

There are 11 different sums.

Step-by-step explanation:

When you roll two dice, the smallest number you can get is 2, and the largest 12, and you can get all in between. So 12-2 is equal to 10, but we have to add another 1 because 2 counts. So the answer is 11.

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Answer:

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Step-by-step explanation:

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A Square was altered so that one side is increased by 9 inches in the other side is decreased by 2 inches.The area of the result
LekaFEV [45]

Let s represent the length of any one side of the original square.  The longer side of the resulting rectangle is s + 9 and the shorter side s - 2.

The area of this rectangle is (s+9)(s-2) = 60 in^2.

This is a quadratic equation and can be solved using various methods.  Let's rewrite this equation in standard form:  s^2 + 7s - 18 = 60, or:

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4 0
3 years ago
Consider the following operations on the number 8.82 x 10^-2. Without using a calculator, decide which would give a significantl
Ksenya-84 [330]

Correct question is;

Consider the following operations on the number 8.85 x 10^(-2). Without using a calculator, decide which would give a significantly smaller value than 8.85 x 10^(-2), which would give a significantly larger value, or which would give essentially the same value.

A) 8.85 × 10^(-2) + 6.69 × 10^(5)

B) 8.85 x 10^(-2) - 6.69 x 10^(5)

C) 8.85 x 10^(-2) x 6.69 x 10^(5)

D) 8.85 × 10^(-2) ÷ 6.69 × 10^(5)

Answer:

Option A & B yield essentially the same value.

Option C yields a significantly smaller value

Option D yields a significantly larger value

Step-by-step explanation:

Since given value for the operations is in 10^(-2) indices, then let's convert the operations numbers from 10^(5) indices to 10^(-2).

Thus;

6.69 × 10^(5) = (6.69 × 10^(-7)) × 10^(-2)

Thus;

A) 8.85 × 10^(-2) + 6.69 × 10^(5) is now;

8.85 × 10^(-2) + ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 + (6.69 × 10^(-7))] × 10^(-2)

The 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same

B) 8.85 x 10^(-2) - 6.69 x 10^(5) is now;

8.85 × 10^(-2) - ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 - (6.69 × 10^(-7))] × 10^(-2)

Again the 10^(-7) indices indicates that the initial value of 8.85 × 10^(-2) would not change much and would essentially be the same.

C) 8.85 x 10^(-2) x 6.69 x 10^(5) is now;

(8.85 × 10^(-2)) × ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 × (6.69 × 10^(-7))] × 10^(-2)

When we multiply 8.85 by 6.69 × 10^(-7), the value gotten will be way lower than the initial value of 8.85.

Thus,this operation will give a significantly smaller value.

D) (8.85 × 10-2) ÷ (6.69 × 10^5) is now;

(8.85 × 10^(-2)) ÷ ((6.69 × 10^(-7)) × 10^(-2))

This gives;

[8.85 ÷ (6.69 × 10^(-7))] × 10^(-2)

When we carry out the operation:

8.85 ÷ (6.69 × 10^(-7)), it is essentially equal to (8.85 × 10^(7))/6.69.

This means that the new value would be significantly larger than the initial value of 8.85.

Thus,this operation yields a significantly larger value.

4 0
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4 0
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sammy [17]

Answer:

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1960/ 160= 12.25

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