Question

Which trigonometric ratios are correct for triangle XYZ?

Answer 1

Answer:

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by varying word choice

by varying sentence lengths

by varying sentence structures

by including interesting details

by providing vivid descriptions

Step-by-step explanation:

Answer 2

Answer:

$tan(Y)=\frac{8}{15}$

$tan(X)=\frac{15}{8}$

$sin(Y)=\frac{8}{17}$

Step-by-step explanation:

The complete question in the attached  figure

Verify each case

Part 1) tan(Y)

we know that

The tangent of angle Y is equal to divide the opposite side angle Y by the adjacent side to angle Y

so

$tan(Y)=\frac{XZ}{YZ}$

substitute the given values

$tan(Y)=\frac{8}{15}$

Part 2) cos(X)

we know that

The cosine of angle X is equal to divide the adjacent side angle X by the  hypotenuse

so

$cos(X)=\frac{XZ}{XY}$

substitute the given values

$cos(X)=\frac{8}{17}$

Part 3) tan(X)

we know that

The tangent of angle X is equal to divide the opposite side angle X by the adjacent side to angle X

so

$tan(X)=\frac{YZ}{XZ}$

substitute the given values

$tan(X)=\frac{15}{8}$

Part 4) sin(Y)

we know that

The sine of angle Y is equal to divide the opposite side angle Y by the hypotenuse

so

$sin(Y)=\frac{XZ}{XY}$

substitute the given values

$sin(Y)=\frac{8}{17}$

Part 5) cos(Y)

we know that

The cosine of angle Y is equal to divide the adjacent side angle Y by the  hypotenuse

so

$cos(Y)=\frac{YZ}{XY}$

substitute the given values

$cos(Y)=\frac{15}{17}$