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Setler79 [48]
3 years ago
11

Calculate dy/dx when y^2 = (3x + 1)^3 / 9x + 2 Pick included

Mathematics
1 answer:
nata0808 [166]3 years ago
8 0
<span> y^2 = (3x + 1)^3 / 9x + 2
2*y*(dy/dx)=(9</span>(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ ((9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(9x + 2) -((9*(3x + 1)^3))/ (2*y*(9x + 2)^2)
(dy/dx)=(9(3x + 1)^2*(6x + 1))/ (2*y*(9x + 2)^2)
 answer 
 A
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soldi70 [24.7K]

Answer:

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3 years ago
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