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3 years ago

8

a boy sold his bike and accessories for $168 if he received 3 times as much for the bike as for the accessories how much did he

receive for the bike?

1 answer:

Veronika [31]3 years ago

3 0

168/4 to get the bike and the accessories to get 42
42x3=126

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Expand the following: 1/3(6/5x-3)

Strike441 [17]

<span>x in (-oo:+oo)</span><span>

(1/3)*((6/5)*x-3) = 0</span><span>

1/3*(6/5*x-3) = 0</span><span>
( 1/3 )</span><span>

1/3 = 0</span><span>

x belongs to the empty set</span><span>

( 6/5*x-3 )</span><span>

6/5*x-3 = 0 // + 3</span><span>

6/5*x = 3 // : 6/5</span><span>

x = 3/6/5</span><span>

x = 5/2</span><span>

x = 5/2</span>

7 0

3 years ago

Read 2 more answers

The dimensions of a rectangular prism are shown below. Length 1 1/3 feet Width 1 foot length 2 1/3 feet. The lengths of the side

zysi [14]

Answer:

84 cubes

Step-by-step explanation:

Given,

The dimension of the rectangular prism are,

$1\frac{1}{3}\text{ ft }\times 1\text{ ft }\times 2\frac{1}{3}\text{ ft }$

Hence, the volume of the prism,

$V=1\frac{1}{3}\times 1\times 2\frac{1}{3}$

$=\frac{4}{3}\times \frac{7}{3}$

$=\frac{28}{9}\text{ cube ft}$

Now, the volume of a cube = side³,

If side = $\frac{1}{3}$ ft,

Then the volume of each cube,

$V'=(\frac{1}{3})^3=\frac{1}{27}\text{ cube ft}$

Hence, the number of cubes that can be packet in the prism

$=\frac{V}{V'}$

$=\frac{28/9}{1/27}$

$=\frac{27\times 28}{9}$

$=3\times 28$

$=84$

8 0

4 years ago

the volume of a cone of radius r and height h is given by v=1/3pir^2h. If the radius and height is both increasing at a constant

Tamiku [17]

Answer:

The rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters is $24\pi \:\frac{cm^3}{s}$

Step-by-step explanation:

This is a related rate problem because you know a rate and want to find another rate that is related to it. If 2 variables both vary with respect to time and have a relation between them, we can express the rate of change of one in terms of the other.

From the information given we know:

$\frac{dr}{dt}=\frac{1}{2}\:\frac{cm}{s}$
$\frac{dh}{dt}=\frac{1}{2}\:\frac{cm}{s}$
The volume of a cone of radius r and height h is given by $V=\frac{1}{3} \pi r^2 h$

We want to find the rate of change of the volume $\frac{dV}{dt}$ when the height is 9 centimeters and the radius is 6 centimeters.

Applying implicit differentiation to the formula of the volume of a cone we get

$\frac{dV}{dt}=\frac{1}{3}\pi [r^2\frac{dh}{dt}+2rh\frac{dr}{dt} ]$

Substituting the values we know into the above formula:

$\frac{dV}{dt}=\frac{1}{3}\pi [(6)^2\frac{1}{2}+2(6)(9)\frac{1}{2} ]\\\\\frac{dV}{dt}=\frac{1}{3}\pi[18+54]\\\\\frac{dV}{dt}=\frac{72\pi}{3}=24\pi \:\frac{cm^3}{s}$

5 0

4 years ago

GIVING 40 POINTS PLEASE ANSWER CORRECT WILL REPORT PLEASE HURRY!!!

dimulka [17.4K]

Answer:

Should be - 5x + 5/6

Step-by-step explanation:

3 0

3 years ago

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Please help.. <br><br> i think the first and fourth are the correct answers but im not 100% sure

Dimas [21]

This one is correct good job,anymore questions

8 0

4 years ago

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