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3 years ago

Please help with these

Mathematics

1 answer:

kherson [118]3 years ago

4 0

The answers are as follows.

a. 9x

In order to get this, you need to reevaluate 64 as a base of 4. Since 64 is equal to 4^3, we can rewrite the right side as

64^3x = (4^3)^3x = 4^9x

Which gives you the first answer.

b. 10

Similar to the first problem, we need to express 16 as a base of 2. 2^4 is equal to 16, so we use that in it's place and simplify.

16^5/2 = (2^4)^5/2 = 2^20/2 = 2^10

c. Sqrt(7.31)

This one is more simple. Raising something to a 1/2 power (.5) is the same as taking the square root.

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Question 2 of 5

jeyben [28]

Answer:

Step-by-step explanation:

Given expression :

1 + 24 + ( + 3) = 1

Bring the number 1 to the left side of the equal sign. The positive 1 becomes negative 1 when brought towards the left side of the equal sign.

1 + 24 + ( + 3) - 1 = 0

Now, opening the bracket, we get

1 + 24 + 3 - 1 = 0

Negative 1 and positive 1 will get cancel

24 + 3 = 0

or 27

Therefore, the value of the numerical expression 1 + 24 + ( + 3) = 1 is 27.

8 0

3 years ago

Carter and his family are driving from Atlanta to Raleigh. They drive for 2 hours and 45 minutes at an average speed of 60 miles

bija089 [108]

The answer is C. Hope this helps :)

8 0

2 years ago

In △ABC, m∠A=39°, a=11, and b=13. Find c to the nearest tenth.

Talja [164]

For this problem, we are going to use the <em>law of sines</em>, which states:

$\dfrac{\sin{A}}{a} = \dfrac{\sin{B}}{b} = \dfrac{\sin{C}}{c}$

In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side, $B$ . Then, we can find the third side. Using the law of sines, we can find:

$\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{B}}{13}$

We can use this to solve for $B$ :

$13 \cdot \dfrac{\sin{39^{\circ}}}{11} = \sin{B}$

$B = \sin^{-1}{\Big(13 \cdot \dfrac{\sin{39^{\circ}}}{11}\Big)} \approx 48.1$

Now, we can find $C$ :

$C = 180^{\circ} - 48.1^{\circ} - 39^{\circ} = 92.9^{\circ}$

Using this, we can find $c$ :

$\dfrac{\sin{39^{\circ}}}{11} = \dfrac{\sin{92.9^{\circ}}}{c}$

$c = \dfrac{11\sin{92.9^{\circ}}}{\sin{39^{\circ}}} \approx \boxed{17.5}$

c is approximately 17.5.

8 0

2 years ago

Is it true or false?? please help me.

Alecsey [184]

Answer:

its true darlin

boom baby:

6 0

3 years ago

What is the volume of this rectangular prism?(HURRY)

Sonbull [250]

Answer:

295.2

Step-by-step explanation:

3 0

3 years ago

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