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Leno4ka [110]
3 years ago
8

Which fractions are greater than 5/10 ? Choose exactly two answers that are correct.

Mathematics
2 answers:
lakkis [162]3 years ago
8 0
6/10 or 3/5
7/10
What are the choices for the answer?
WINSTONCH [101]3 years ago
4 0
Hey there! 

Question: what fractions are greater than \frac{5}{10} ? Choose exactly 2 answers


Well honestly, we can find our answer by converting the answers to decimals 

\frac{5}{10} =  \frac{1}{2}  = 0.5 \\ \\ \\ \\  \frac{6}{12}  =  \frac{1}{2} = 0.5 \\ \\  \frac{2}{3}  =  \frac{2}{3} = 0.667 \\ \\  \frac{63}{100} =  \frac{63}{100} = 0.63 \\ \\  \frac{3}{8}  =  \frac{3}{8}   = 0.375

It can't be A because it is equivalent to the fraction 

It can be B because it is greater than the fraction 

It can be C because it is also greater than the fraction 

It can't be D because it is lesser than the fraction 

Answer:B,C

Good luck on your assignment and enjoy your day! 

~LoveYourselfFirst:)
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Mr. and mrs. lorenzo want to buy a home valued at $213,500. if they have 18% of this amount saved for a down payment, how much h
Vesnalui [34]

Option d is the correct answer. $38,430.00 is the amount saved for a down payment given that Mr. and Mrs. Lorenzo want to buy a home valued at $213,500 and they have 18% of this amount saved for the down payment. This can be obtained by using percentage formula.

<h3>How much have they saved?</h3>

The percentage of a number can be obtained using percentage formula,

If P% of X is Y then it can be denoted using the formula of percentage as,

⇒ P% of X = Y

⇒ P% × X = Y   (where P% is P/100)

Here in the question it is given that,

  • Mr. and Mrs. Lorenzo want to buy a home valued at $213,500
  • They have 18% of this amount saved for a down payment

We have to find the amount they saved for the down payment.

  • Given that the total amount = $213,500
  • Percentage they are saving = 18%

The amount they saved for the down payment,

18% of the total amount = 18% of $213,500

Using the percentage formula we get,

18% of $213,500 = 18% × $213,500  

18% of $213,500 = 18/100 × $213,500

18% of $213,500 = $ 38,430.00

Hence Option d is the correct answer. $38,430.00 is the amount saved for a down payment given that Mr. and Mrs. Lorenzo want to buy a home valued at $213,500 and they have 18% of this amount saved for the down payment.

Learn more about percentages here:

brainly.com/question/14366896

#SPJ4

3 0
2 years ago
A manufacturing company regularly conducts quality control checks at specified periods on the products it manufactures. Historic
Rina8888 [55]

Answer:

The probability that none of the LED light bulbs are​ defective is 0.7374.

Step-by-step explanation:

The complete question is:

What is the probability that none of the LED light bulbs are​ defective?

Solution:

Let the random variable <em>X</em> represent the number of defective LED light bulbs.

The probability of a LED light bulb being defective is, P (X) = <em>p</em> = 0.03.

A random sample of <em>n</em> = 10 LED light bulbs is selected.

The event of a specific LED light bulb being defective is independent of the other bulbs.

The random variable <em>X</em> thus follows a Binomial distribution with parameters <em>n</em> = 10 and <em>p</em> = 0.03.

The probability mass function of <em>X</em> is:

P(X=x)={10\choose x}(0.03)^{x}(1-0.03)^{10-x};\ x=0,1,2,3...

Compute the probability that none of the LED light bulbs are​ defective as follows:

P(X=0)={10\choose 0}(0.03)^{0}(1-0.03)^{10-0}

                =1\times 1\times 0.737424\\=0.737424\\\approx 0.7374

Thus, the probability that none of the LED light bulbs are​ defective is 0.7374.

6 0
3 years ago
What relation does not have an initial value of 50
Mamont248 [21]
I guess itz B because with the rest, a number can be added to get exactly 50. Example C. y= 50x. x could be 1 which is still 50 and D. y=50-x and x could be 0 which is still 50 whiles A. y=50 remains 50

4 0
3 years ago
Please help!
seropon [69]

Answer:

0.246¯¯¯¯ written as a fraction in simplest form?

the answer is 1000÷246

8 0
3 years ago
Suppose quantity s is a length and quantity t is a time. Suppose the quantities v and a are defined by v = ds/dt and a = dv/dt.
finlep [7]

Answer:

a) v = \frac{[L]}{[T]} = LT^{-1}

b) a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}

c) \int v dt = s(t) = [L]=L

d) \int a dt = v(t) = [L][T]^{-1}=LT^{-1}

e) \frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}

Step-by-step explanation:

Let define some notation:

[L]= represent longitude , [T] =represent time

And we have defined:

s(t) a position function

v = \frac{ds}{dt}

a= \frac{dv}{dt}

Part a

If we do the dimensional analysis for v we got:

v = \frac{[L]}{[T]} = LT^{-1}

Part b

For the acceleration we can use the result obtained from part a and we got:

a = \frac{[L}{T}^{-1}]}{{T}}= L T^{-1} T^{-1}= L T^{-2}

Part c

From definition if we do the integral of the velocity respect to t we got the position:

\int v dt = s(t)

And the dimensional analysis for the position is:

\int v dt = s(t) = [L]=L

Part d

The integral for the acceleration respect to the time is the velocity:

\int a dt = v(t)

And the dimensional analysis for the position is:

\int a dt = v(t) = [L][T]^{-1}=LT^{-1}

Part e

If we take the derivate respect to the acceleration and we want to find the dimensional analysis for this case we got:

\frac{da}{dt}= \frac{[L][T]^{-2}}{T} = [L][T]^{-2} [T]^{-1} = LT^{-3}

7 0
3 years ago
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