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8090 [49]
3 years ago
15

Help me figure out the last two please

Mathematics
1 answer:
yawa3891 [41]3 years ago
3 0

Answer:

1)\ x = 5

2)\ x = 14

3) \ x = 15,\ y = 2

Step-by-step explanation:

1) Given that M<1 = 95 + 7x and M<2 = 55 - x, you should look on the diagram to see what type of angles M<1 and M<2 are.

On the diagram at the top, angles 1 and 2 appear to be supplementary angles, meaning they add up to 180 degrees. You can apply this information to creating an equation:

  • M<1 + M<2 = 180°
  • (95 + 7x) + (55 - x) = 180

Now you can solve this equation by combining like terms on the left-hand side of the equation.

  • 150+6x=180

Subtract 150 from both sides of the equation in order to isolate the variable x.

  • 6x=30

Divide both sides of the equation by 6 in order to isolate the variable x completely.

  • x=5

2) You are given that M<3 = 5x + 12 and M<4 = 7x - 16, so look on the diagram at the top to find out what type of angles they are.

Angles 3 and 4 appear to be alternate exterior angles, meaning that they are equal to each other as stated by the Alternate Exterior Angles Theorem. You can use this information to make an equation where M<3 = M<4.

  • M<3 = M<4
  • 5x+12=7x-16

Subtract 5x from both sides of the equation, and add 16 to both sides of the equation.

  • 28=2x

Divide both sides of the equation by 2 to isolate the variable x completely.

  • 14=x \rightarrow x=14

3) Given that M<1 = 7y + 16, M<2 = 2x, and M<3 = 4x - 30, look on the diagram at the bottom to find out what type of angles they are.

Since angles 2 and 3 include an "x" variable, you should start with them first  in order to be able to solve for x. Angles 2 and 3 are complementary angles, meaning that they are equal to each other based on the Complementary Angles Theorem. Translate this information into an equation:

  • M<2 = M<3
  • 2x=4x-30

Subtract 2x from both sides of the equation and add 30 to both sides of the equation.

  • 30=2x

Divide both sides of the equation by 2 in order to isolate the variable x completely.

  • 15=x \rightarrow x=15

Now to solve for y - based on the diagram, you can see that angle 1 and angle 2 are vertical angles, meaning that they are equal to each other based on the Vertical Angles Theorem.

You can make them equal to each other in an equation:

  • M<1 = M<2
  • 7y+16=2x

We solved for x and know that it is 15, so substitute 15 into the equation for x.

  • 7y+16=2(15)
  • 7y+16=30

Subtract 16 from both sides of the equation.

  • 7y=14

Divide both sides of the equation by 7 to isolate the variable x.

  • y=2

Hope this helped! Comment below if you have any clarifying questions.

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A tank with a capacity of 1000 L is full of a mixture of water and chlorine with a concentration of 0.02 g of chlorine per liter
faltersainse [42]

At the start, the tank contains

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Pure water is pumped into the tank, so no chlorine is flowing into it, but is flowing out at a rate of

(<em>c</em> (<em>t</em> )/(1000 + (10 - 25)<em>t</em> ) g/L) * (25 L/s) = 5<em>c</em> (<em>t</em> ) /(200 - 3<em>t</em> ) g/s

In case it's unclear why this is the case:

The amount of liquid in the tank at the start is 1000 L. If water is pumped in at a rate of 10 L/s, then after <em>t</em> s there will be (1000 + 10<em>t</em> ) L of liquid in the tank. But we're also removing 25 L from the tank per second, so there is a net "gain" of 10 - 25 = -15 L of liquid each second. So the volume of liquid in the tank at time <em>t</em> is (1000 - 15<em>t </em>) L. Then the concentration of chlorine per unit volume is <em>c</em> (<em>t</em> ) divided by this volume.

So the amount of chlorine in the tank changes according to

\dfrac{\mathrm dc(t)}{\mathrm dt}=-\dfrac{5c(t)}{200-3t}

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\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{200-3t}=0

\dfrac1{(200-3t)^{5/3}}\dfrac{\mathrm dc(t)}{\mathrm dt}+\dfrac{5c(t)}{(200-3t)^{8/3}}=0

\dfrac{\mathrm d}{\mathrm dt}\left[\dfrac{c(t)}{(200-3t)^{5/3}}\right]=0

\dfrac{c(t)}{(200-3t)^{5/3}}=C

c(t)=C(200-3t)^{5/3}

There are 20 g of chlorine at the start, so <em>c</em> (0) = 20. Use this to solve for <em>C</em> :

20=C(200)^{5/3}\implies C=\dfrac1{200\cdot5^{1/3}}

\implies\boxed{c(t)=\dfrac1{200}\sqrt[3]{\dfrac{(200-3t)^5}5}}

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x = 175:7 = 25

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