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2 years ago

10

A rectangular lawn 80 m x 60 m has two roads each 10m wide running in the middle of it, one parallel to the length and the other

parallel to the breadth. Find the cost of gravelling them at ₹ 1.20 per sq meter.

1 answer:

Ipatiy [6.2K]2 years ago

6 0

Answer:

₹1680

Step-by-step explanation:

<u>Road</u> <u>Length (m)</u> <u>Width (m)</u> <u>Area (</u> $m^{2}$ <u>)</u>

1 80 10 800

2 60 10 600

(800+600) = 1400 <u>(</u> $m^{2}$ <u>)</u>

<u></u>

1400 <u>(</u> $m^{2}$ <u>)</u>*(₹ 1.20/m) = ₹1680

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Lines k and n intersect on the y-axis

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a) The equation of line k is:

$y = -\frac{202}{167}x + \frac{598}{167}$

b) The equation of line j is:

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The equation of a line, in <u>slope-intercept formula</u>, is given by:

$y = mx + b$

In which:

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b is the y-intercept, which is the value of y when x = 0.

Item a:

Line k intersects line m with an angle of 109º, thus:

$\tan{109^{\circ}} = \frac{m_2 - m_1}{1 + m_1m_2}$

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$y = -\frac{202}{167}x + b$

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$y = -\frac{202}{167}x + b$

$6 = -\frac{202}{167}(-2) + b$

$b = 6 - \frac{404}{167}$

$b = \frac{6(167)-404}{167}$

$b = \frac{598}{167}$

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$y = -\frac{202}{167}x + \frac{598}{167}$

Item b:

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$6 = \frac{167}{202}(-2) + b$

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$b = \frac{1546}{202}$

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A similar problem is given at brainly.com/question/16302622

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Step-by-step explanation:

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