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statuscvo [17]
3 years ago
11

Work out $216 as a percentage of $600

Mathematics
2 answers:
dusya [7]3 years ago
3 0

Answer:

36%

Step-by-step explanation:

Put it into a fraction:

216/600

Next divide:

216/600= 0.36

Turn the decimal into a percentage:

0.36 = 36%

216 as a percentage of 600 is equal to 36%.

liberstina [14]3 years ago
3 0

Answer:

36%

Step-by-step explanation:

216 / 600

0.36

0.36 * 100 = 36%

Best of Luck!

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What is the equation of the coordinate A and B if they are (4,7), (6,3) respectively. What is the equation of the straight line.
Nesterboy [21]

Answer: y+2x=15

Step-by-step explanation:

Given

Two points A and B are (4,7) and (6,3) respectively

Using two-point form

\Rightarrow \dfrac{y-y_1}{x-x_1}=\dfrac{y_2-y_1}{x_2-x_1}

Putting values

\Rightarrow \dfrac{y-7}{x-4}=\dfrac{3-7}{6-4}\\\\\Rightarrow \dfrac{y-7}{x-4}=\dfrac{-4}{2}=-2\\\\\Rightarrow y-7=-2x+8\\\\\Rightarrow y+2x=15

3 0
3 years ago
You have $125. You want to go to the carnival with friends. Admission is $45 and tickets for the rides are $8 each. Which inequa
anastassius [24]

Answer:

I think you're SOL there buddy

Step-by-step explanation:

7 0
2 years ago
What percent of 600 is 12
Hitman42 [59]
<span>What percent of 600 is 12?
In order to get what percent of 600 is 12, we need to formulate the equation.

12 = ___ * 600
12 = 600P
P = 12 / 600 
P = 0.02

Percentage must be in hundred. So multiply 0.02 by 100
= 0.02 * 100
= 2%

So, 2% of 600 is equal to 12.</span>
7 0
3 years ago
Convert 1047 to base 5​
mihalych1998 [28]

Answer:

dadasdadadadad

Step-by-step explanation:

7 0
3 years ago
How do you do this question?
arlik [135]

Answer:

\left \{ {{x=2+3\cos t} \atop {y\:=-1+3\sin t}} \right. => \pi \leq t \leq 5\pi

Step-by-step explanation:

The standard equation of a circle centered at (a,b) with radius r would be (x - a)^2 + (y - a)^2 = r^2

This example represents a circle with center (2, - 1) having a radius of 3

The parametric equation of a circle centered at (0,0) would be;

x = r cos t,

y = r sin t

And so when centered at (a, b) we would have;

x = a + r cos t,

y = b + r sin t

In this case x = 2 + 3 cos t, and y = - 1 + 3 cos t

Now if the particle starts at (-1, - 1), correspondent to a start parameter of t = π, we need two revolutions so it should be that t = π + 2 * 2π = 5π.

\left \{ {{x=2+3\cos t} \atop {y\:=-1+3\sin t}} \right. => \pi \leq t \leq 5\pi

6 0
3 years ago
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