Answer:
36 ft by 16 ft
Step-by-step explanation:
To solve this problem, you need to find dimensions of a rectangle such that the perimeter is 104 ft and the area is 576 ft. The perimeter is twice the sum of length and width, so the sum of length and width is 52 ft.
The area is the product of length and width, so if w represents the width, we have ...
w(52 -w) = 576
w² -52w = -576 . . . . . eliminate parentheses, multiply by -1
w² -52w +26² = 26² -576 . . . . . . complete the square
(w -26)² = 676 -576 = 100
w = 26 ±√100 = {16, 36}
If the width is the short dimension, it is 16 feet. Then the length is 36 feet.
This is the answer!! Also I use Photomath to help with my hw!
You put the 15x + 100 on the angle CEB instead of CED. If you put it in the right spot, it should work out fine since they are vertical angles.
Finding two geometric means between 10 and 125:
a 1 = 10, a 4 = 1250
a 4 = a 1 * q^3
1250 = 10 * q^3
q^3 = 1250 : 10
q^3 = 125
q = 5
a 2 = 10 * 5 = 50
a 3 = 10 * 5² = 10 * 25 = 250
Answer: The two geometric means are: 50 and 250, since 10, 50, 250 , 1250 forms a geometric sequence.
Answer:
The coordinates are (50, 103)
Step-by-step explanation:
The three hallways are AB, BC, CD.
The co-ordinate of D is (50, 75).
The school's flagpole is 28 meters right of the point D.
Hence the y-coordinate for the flagpole will be same as D, that is 75.
The x-coordinate will be (28 + 75) = 103.
The location of the school's flagpole will be represented by (50, 103)
