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Feliz [49]
2 years ago
10

How do you solve 5p+2=4p-1

Mathematics
2 answers:
Grace [21]2 years ago
6 0
5p+2=4p-1
1p+2=-1
1p=-3
p=-3
musickatia [10]2 years ago
6 0

Answer:

The equation would be p=-3

Step-by-step explanation:

First of all, you must take into account that all the terms with the letter p must be on the left side of the equation, the other terms must be on the right side.

First step

The 4p term must be passed to the left with opposite sign

5p+2-4p=-1

Second step

The +2 term from the left must be passed to the right with opposite sign

5p-4p=-1-2

Third step

You must perform the operations. The equation would be:

p=-3

Thus, the equation would be p=-3

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A. Find the dimensions of the original painting.

 

Since the scale is 1 in : 40 cm

2 in ( 40 cm / 1 in) = 80 cm

1.5 in ( 40 cm / 1 in) = 60 cm

80 cm by 60 cm

 

B. Find the area of the original painting.

<span>A =  80 cm x 60 cm = 4800 sq cm</span>

 

C. Since 1 inch is 2.54 cm, find the dimensions of the original painting in inches.

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60 cm ( 1 in / 2.54 cm) = 23.6 in

 

D, Find the area of the original painting in square inches.

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3 years ago
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Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is \hat p_1 = 1020/1272 = 85/106 = 0.8\overline {0188679245283} ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is \hat p_2 = 5343/6238 ≈ 0.8565

c) We have the following two way table;

\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}

The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

95 \% \ CI \approx  0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

6 0
2 years ago
Hey im back with this map i need help
Katena32 [7]

Answer:

m<5= 46 degrees

m<8= 134 degrees

Step-by-step explanation:

m<5: all you need to do is subtract 134 from 180

m<8: m<2 and m<8 have the same angle

7 0
2 years ago
Math (10 points) help please
nevsk [136]

Answer:

I would help but I am not good with graphing.

5 0
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