3 years ago

Kim ate 3/10 of a bag of chips, sandy ate 3/7 of a bag, and jeff ate 3/9 of a bag. who ate the most

Mathematics

2 answers:

aksik [14]3 years ago

6 0

Answer:

sandy

Step-by-step explanation:

3/10 = .3

3/7=.43

3/9=.333333

sandy then jeff then kim

Gwar [14]3 years ago

6 0

Answer:

3/10 =0.3 3/7 = 0.43 3/9=0.33

Therefore 3/9 is larger than Kim so Sandy must be the answer.

As 3/10 is a smaller portion.

Just like 1/3 is smaller than 2/3

or 1/4 is smaller than 1/3

or 1/4 is smaller than 1/2

Step-by-step explanation:

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