Question

Write the equation of a line in point-slope form that is parallel to the line y = 3x +6 and passes through the point (-5, 8)

Answer 1

Answer:  y-8 = 3(x+5)

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Explanation:

The slope of the given line y = 3x+6 is m = 3
Anything parallel to this will also have the same slope (of m = 3)

The given point is (-5,8), so this means (x1,y1) = (-5,8)
further breaking down to x1 = -5 and y1 = 8

The three pieces of info we have are: m = 3, x1 = -5 and y1 = 8
Which are then plugged into the point-slope form below
y-y1 = m(x-x1)
y-8 = 3(x - (-5))
y-8 = 3(x+5) ... make sure to simplify as much as possible