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tester [92]
3 years ago
13

Which methods could you use to calculate the y-coordinate of the midpoint of a vertical line segment with endpoints at (0, 0) an

d (0, 15?
Mathematics
1 answer:
Tcecarenko [31]3 years ago
4 0
The y-coordinate of the midpoint of a line segment is the average of the y-coordinates of the endpoints of the line segment.

This is: call y1 the y-coordinate of one endpoint and y2 the y-coordinate of the other endpoint of the line segment, then the midpoint is [y1 + y2] / 2.

The method, then, is to add the two y-coordinates and divide by 2.

For the vertical line segment with endpoints  (0,0) and (0,15) theprocedure is [0 + 15] / 2 = 15/2 = 7.5, and the result is 7.5
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-4rover4+5rover3 please help me
Alchen [17]

Solution, \frac{-4r}{4}+\frac{5r}{3}=\frac{2r}{3}

Steps:

\frac{-4r}{4}+\frac{5r}{3}

\frac{-4r}{4},\\\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{-a}{b}=-\frac{a}{b},\\-\frac{4r}{4},\\\mathrm{Divide\:the\:numbers:}\:\frac{4}{4}=1,\\-r,\\-r+\frac{5r}{3}

\mathrm{Convert\:element\:to\:fraction}:\quad \:r=\frac{r3}{3},\\\frac{5r}{3}-\frac{r\cdot \:3}{3}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c},\\\frac{5r-r\cdot \:3}{3}

5r-r\cdot \:3,\\\mathrm{Add\:similar\:elements:}\:5r-3r=2r,\\\frac{2r}{3}

The\:Correct\:Answer\:Is\:\frac{2r}{3}

Hope\:This\:Helps!!!

-Austint1414

5 0
3 years ago
Evaluate x6 + y(-9)<br> When x= -2, y = 4
11111nata11111 [884]

Answer:

the answer is -48. _______

4 0
3 years ago
It costs $20 per hour to bowl and $3 for the shoes rental. Write an algebraic expression to represent the cost for n hours. How
ValentinkaMS [17]
(20n+3)
n = number of hours = 1
(20(1)+3) = 23
$23
6 0
3 years ago
Grade 9 math plzz helpp a or b or c or d
hram777 [196]

Answer:

g(x) = 3^{x -4}

Step-by-step explanation:

Given

f(x) = 3^x

g(x) = f(x) 4 units left

Required

Find g(x)

When a point is translated 4 units left, the rule is:

x \to x - 4

So, we have:

g(x) = f(x-4)

f(x-4) is calculated as:

f(x-4) = 3^{x -4}

Hence:

g(x) = 3^{x -4}

4 0
3 years ago
A ball is thrown into the air from a height of 9cm above the ground, and its height is given by S=128+32t-16t^2, where t is the
OverLord2011 [107]
-16t² + 32t + 128 = 0
-16t² + 64t - 32t + 128 = 0
-16t(t - 4) - 32(t - 4)
(-16t - 32)(t - 4) = 0
-16t -32 = 0      t - 4 = 0
-16t = 32          t = 4
t = -2

t = -2 and t = 4 are the values that makes S = 0.
Yes, because if you apply either of  these values alone, S will be 0.
6 0
3 years ago
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