<span>The range of Cos(x) is [-1,1]. Therefore the range of ln(Cos(x)) will be the image of [-1,1] using the natural log function. However, the domain of ln(x) is (0,infinity) and the log function is strictly increasing with vertical asymptote at "x=0". Therefore, the range of ln(Cos(x)) will be:
(- infinity, ln(1) ] = (-infinity, 0] !</span><span>so its true </span>
The answer C.
Since the common ratio is 2
You just need to multiply each number with two to get the next number
14x2=28
28x2=56
56x2= 112
Answer:
15.625
Step-by-step explanation:
V=wxhxl=2.5x2.5x2.5=15.625
Part I)
The module of vector AB is given by:
lABl = root ((- 3) ^ 2 + (4) ^ 2)
lABl = root (9 + 16)
lABl = root (25)
lABl = 5
Part (ii)
The module of the EF vector is given by:
lEFl = root ((5) ^ 2 + (e) ^ 2)
We have to:
lEFl = 3lABl
Thus:
root ((5) ^ 2 + (e) ^ 2) = 3 * (5)
root ((5) ^ 2 + (e) ^ 2) = 15
Clearing e have:
(5) ^ 2 + (e) ^ 2 = 15 ^ 2
(e) ^ 2 = 15 ^ 2 - 5 ^ 2
e = root (200)
e = root (2 * 100)
e = 10 * root (2)
Answer:
1/22
Step-by-step explanation:
assuming that the marbles drawn are not replaced:
P(red) = 3/12 or 1/4
P(green) = 4/11
P(blue) = 5/10 or 1/2
multiply the probabilities together:
1/4 x 4/11 x 1/2 = 1/22
