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Sonja [21]
3 years ago
7

Mrs. Nelson has a rectangular flower box that is 5 feet long and 2 feet tall. She wants the width of the box to no more than 5 f

eet. If the width is a whole number, what are the possible volumes for the flower box?

Mathematics
1 answer:
d1i1m1o1n [39]3 years ago
7 0
Volume = length x width x height.
if the width has to be a whole number no more than 5 then the only options for the width is 1, 2, 3, 4, or 5.
V=5x1x2
V=10
V=5x2x2
V=20
V=5x3x2
V=30
V=5x4x2
V=40
V=5x5x2
V=50
the possible volumes are as follows: 10, 20, 30, 40, and 50.
make sure in your answer that you label your volumes so you write ft^3 after every volume answer.

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Suppose a triangle has two sides of length 3 and 4 and that the angle between these two sides is 60 degrees . What is the length
Darya [45]

Answer:

  √13 ≈ 3.6056

Step-by-step explanation:

The Law of Cosines can be used to figure this. If the third side is "c", then it tells you ...

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  c² = 3² + 4² -2(3)(4)(cos(60°)) = 9 + 16 - 24(1/2) = 13

  c = √13 ≈ 3.6056

The length of the third side is √13, about 3.6056.

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Answer:

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6 0
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Dmitry_Shevchenko [17]
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2 years ago
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A circle has a radius of 6. An arc in this circle has a central angle of 48º.
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6 0
2 years ago
It takes 13 more copies of the angle for the last angle to overlap the first horizontal ray. What is the measure of each angle?
nalin [4]
Missing part in the heading of the question:
For this question, use the diagram shown. The diagram shows the result of constructing a copy of an angle adjacent to one of the rays of the original angles. Assume the pattern continues.

Answer:
measure of each angle = 24°

Explanation:
The diagram shows two angles, if we add 13 more copies, the number of angles would be 15 angles

Now, when the 15 angles are drawn, the last angle would overlap with the first horizontal ray.
This means that the angles form one complete rotation around the point.

This means that the sum of the 15 angles together is 360°.

We know the all 15 angles are equal. Assume that the measure of each is x.
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Hope this helps :)

6 0
3 years ago
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