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oksian1 [2.3K]
3 years ago
14

Someone please find the constant proportionality!!!

Mathematics
1 answer:
Andru [333]3 years ago
8 0

Answer:

Possible - 1 and 0

.....

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Luisa has 24 students in her class. 3/4 of the students speak spanish as well as english. How many students speak both spanish a
neonofarm [45]
Divide 24 by 4 because the denominator is 4..
24÷4=6
Multiply 6 by 3 because the numerator is 3.
6×3=18
<span>18/24 students speak both Spanish and English</span>
6 0
2 years ago
Read 2 more answers
What is 12 1/2% of 256
s344n2d4d5 [400]
To determine this, we need to set up fractional proportions.
First, put 12.5% (what we're looking for) over 100%, which is the total (256).
12.5/100 should be your first fraction.
Now, put x over 256, x being 12.5% of 256.
x/256 should be your second fraction.
Now put these two fractions as an equation.
x/256 = 12.5/100
This may be where things get tricky if you don't pay attention.
Cross multiply the top number (numerator) of x/256 with the bottom number (denominator) of 12.5/100.
You should end up with 100x.
Now, cross multiply the top number of 12.5/100 with the bottom number of x/256.
You should end up with 3200.
Now our equation is:
100x = 3200
Divide both sides by 100 to get x.
100x/100 = x
3200/100 = 32
x = 32 is now your simplified equation.
Your final answer is:
32 is 12.5% of 256.
Also, since 12.5% is 1/8 of 100%, we can test our answer.
Multiply 32 by 8 to get 8/8 (100%).
32 x 8 = 256.
Your answer is 32.
I hope this helps!

6 0
3 years ago
What is the volume of a right cylinder with a base diameter of 6m and a height of 5m
SOVA2 [1]

Answer:

V≈141.37m³

<h2>explanation :</h2>

3 0
3 years ago
A sports news station wanted to know whether people who live in the North or the South are bigger sports fans. For its study, 17
Free_Kalibri [48]

Using the z-distribution, it is found that the 95% confidence interval for the difference is (-1.3, -0.7).

<h3>What are the mean and the standard error for each sample?</h3>

Considering the data given:

\mu_S = 3.8, n = 175, s_S = \frac{1.7}{\sqrt{175}} = 0.1285

\mu_N = 4.8, n = 152, s_N = \frac{1.2}{\sqrt{152}} = 0.0973

<h3>What is the mean and the standard error for the distribution of differences?</h3>

The mean is the subtraction of the means, hence:

\overline{x} = \mu_S - \mu_N = 3.8 - 4.8 = -1

The standard error is the square root of the sum of the variances of each sample, hence:

s = \sqrt{s_S^2 + s_N^2} = \sqrt{0.1285^2 + 0.0973^2} = 0.1612

<h3>What is the confidence interval?</h3>

It is given by:

\overline{x} \pm zs

We have a 95% confidence interval, hence the critical value is of z = 1.96.

Then, the bounds of the interval are given as follows:

  • \overline{x} - zs = -1 - 1.96(0.1612) = -1.3
  • \overline{x} + zs = -1 + 1.96(0.1612) = -0.7

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
A little help on this question? Picture is below. (For 20 points.)
Elena L [17]

Answer:

a) 3 3/5

b) 18/5

c) 3.6

Hope this helps!

3 0
3 years ago
Read 2 more answers
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