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2 years ago

Solve for x.3-sqrt(x)=0 What is the root? If there is none, choose none. x = 3 x = 9 none

Mathematics

1 answer:

Anon25 [30]2 years ago

8 0

Answer:

x = 9

Step-by-step explanation:

You can solve this problem by isolating the variable.

3-√x = 0

√x = 3 (add √x to both sides of the equation)

x = 9 (square both sides of the equation)

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Find the values of and y the figure given below and choose the appropriate result ABC and XYZ

Yuri [45]

Answer:

y = 8

x = 17

Step-by-step explanation:

We can find the missing values using similarity ratio

15/30 = y/16 cross multiply expressions

30y = 240 divide both sides by 30

y = 8

Now do the same for x

15/30 = x/34 cross multiply expressions

30x = 510 divide both sides by 30

x = 17

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2 years ago

The drama club is washing. cars for a fundraiser. If the rate continues, how many cars will they was in 4 hours?

solong [7]

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2 years ago

The angle 01 is located in Quadrant III, and cos(01) = -30/13

larisa [96]

Answer:

Step-by-step explanation:

Given cos(01) = -30/13 where angle 01 is located in quadrant III. In the third quadrant, both cos and sin are negative. only tan is positive.

To calculate sin(01), we will apply the trigonometry expression as shown below;

cos(01) = -30/13

According to SOH CAH TOA;

cos(01) = adjacent/hypotenuse = -30/13

sin(01) = opposite/ hypotenuse

To get the hypotenuse, we will use the pythagoras theorem

$hyp^{2}=opp^{2}+adj^{2} \\opp^{2}= hyp^{2}-adj^{2}\\opp^{2}= 13^{2} -(-30^{2} )\\opp^{2} = 169+900\\opp^{2}=1069\\opp = \sqrt{1069} \\opp = 32.70\\$

sin(01) = 32.70/13

Since sin is also negaitve in the third quadrant, the value of

sin(01) = -32.70/13

$01 = cos^{-1}- 30/13$

8 0

2 years ago

HELP i need the answers to these! explain if possible:)

IrinaVladis [17]

so one: the middle Angles are all 90 degrees triangles equal 180, the angle opposite of "x" is equal to 34 so 180-90-34=x

two: both angles are equal set it up like an equation and solve for n

three: the corner angle of the right triangle is equal to 61 as well again do 180-(61×2)=x

4: do this equation (<ktu)2+ x = 180 then solve for x

5: not exactly.sure what its asking

hope this helps

5 0

3 years ago

Create a matrix for this system of linear equations, The determinant of the coefficient matrix is

marin [14]

Answer: The determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

Step-by-step explanation: The given system of linear equations is :

$2x+y+3z=13~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\x+2y=11~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\3x+z=10~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)$

We are given to find the determinant of the coefficient matrix and to find the values of x, y and z.

The determinant of the co-efficient matrix is given by

$D=\begin{vmatrix}2 & 1 & 3\\ 1 & 2 & 0\\ 3 & 0 & 1\end{vmatrix}=2(2-0)+1(0-1)+3(0-6)=4-1-18=-15.$

Now, from equations (ii) and (iii), we have

$x+2y=11~~~~~\Rightarrow y=\dfrac{11-x}{2}~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)\\\\\\3x+z=10~~~~~~\Rightarrow z=10-3x~~~~~~~~~~~~~~~~~~~~~~~~~(v)$

Substituting the value of y and z from equations (iv) and (v) in equation (i), we get

$2x+y+3z=13\\\\\Rightarrow 2x+\dfrac{11-x}{2}+3(10-3x)=13\\\\\Rightarrow 4x+11-x+60-18x=26\\\\\Rightarrow -15x+71=26\\\\\Rightarrow -15x=26-71\\\\\Rightarrow -15x=-45\\\\\Rightarrow x=3.$

From equations (iv) and (v), we get

$y=\dfrac{11-3}{2}=4,\\\\z=10-3\times3=1.$

Thus, the determinant of the coefficient matrix is -15 and x = 3, y = 4, z = 1.

3 0

3 years ago