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Misha Larkins [42]
3 years ago
13

Julio considers the reduction of the triangle. 12 in height 21 in base and 8 in height x in base Not drawn to scale What is the

correct cross product that he should use to solve for the missing dimension?

Mathematics
2 answers:
Serhud [2]3 years ago
6 0
To find the cross product, you can set this up as a proportion. Please see the attached paper for one of the proportions you could use.

You would then multiply the numbers that are diagonal from each other.

You would have 21(8) = 12x or
168=12x.

SOVA2 [1]3 years ago
5 0

Answer:

multiply the base x height.

Step-by-step explanation:

B X H = AREA

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Can someone help me with this?
aivan3 [116]

Step-by-step explanation:

The formula for the volume of a sphere is V = 4/3 πr³.

So

Given

Volume (v) = 57ft³

v =  \frac{4}{3} \pi {r}^{3}

57 =  \frac{4}{3}  \times 3.14 \times  {r}^{3}

57 = \frac{12.56}{3} \times    {r}^{3}

57 = 4.19 \times  {r}^{3}

{r}^{3}  =  \frac{57}{4.19}

{r}^{3}  = 13.6

r =  \sqrt[3]{13.6}

Therefore r = 2.4 ft

I gave my answers by rounding off. so if you don't round off then it's answer is 2.3 ft

7 0
3 years ago
Is the answer a,b,c or d​
Natalija [7]

Answer:

C) SSS

Step-by-step explanation:

<em>SSS</em> stands for "<em>side, side, side</em>" and means that we have two triangles with all three sides equal.  

If three sides of one triangle are equal to three sides of another triangle, the triangles are <em>congruent</em>.

5 0
3 years ago
Solve the problem.<br> Find the diameter of a circle that has a circumference of 942 meters.
solong [7]
The answer to the problem is 299.85 m.
3 0
3 years ago
Probe that:<br><img src="https://tex.z-dn.net/?f=%20%5Csec%20%5Calpha%20%20%5Csqrt%7B1%20-%20%20%5Csin%28%20%7B%7D%5E%7B2%7D%20%
Nataly [62]

Step-by-step explanation:

<h3>\sec \alpha  \sqrt{1 -  \sin ^{2}   \alpha }  = 1</h3>

Prove the LHS

Using trigonometric identities

That's

<h3>\cos ^{2}  \alpha  = 1 -  \sin^{2}  \alpha</h3>

<u>Rewrite the expression</u>

We have

<h3>\sec \alpha  \sqrt{ \cos^{2} \alpha  }</h3>

<h3>\sqrt{ { \cos }^{2}  \alpha }  =  \cos \alpha</h3>

So we have

<h3>\sec  \alpha  \times  \cos \alpha</h3>

Using trigonometric identities

<h3>\sec \alpha  =  \frac{1}{ \cos \alpha }</h3>

<u>Rewrite the expression</u>

That's

<h3>\frac{1}{\cos \alpha }  \times  \cos \alpha</h3>

Reduce the expression with cos a

We have the final answer as

<h2>1</h2>

As proven

Hope this helps you

7 0
3 years ago
A test has twenty questions worth 100 points. the test consists of
Sophie [7]
B. False questions worth 3 ...
6 0
3 years ago
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