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alexdok [17]
3 years ago
11

Where is the answer to the expression 4 - 8 located on a horizontal number line?

Mathematics
1 answer:
maw [93]3 years ago
5 0
I have drawn an arrow pointing to where it would be on a number graph 

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The correlation between two scores X and Y equals 0.75. If both scores were converted to Z-scores, then the correlation between
Ilia_Sergeevich [38]

Answer:

  (e)  0.75

Step-by-step explanation:

The correlation coefficient is not affected by translation or scaling of scores. Converting them from "raw scores" to z-scores does not affect their correlation.

The correlation coefficient of the z-scores is 0.75.

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I think b...............................
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Sarah's father was 30 when she was born.
Basile [38]

Answer:

He is B) 45 years old

Step-by-step explanation:

If he was 30 when she was born, he was 40 when she was 10, and he was 45 when she was 15.

15 x 3 = 45

Edit: It can actually be any of them....

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A

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Rate of change is another term for slope

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A manufacturer of precision measuring instruments claims that the standarddeviation in the use of the instruments is less than 0
alexdok [17]

Answer:

i) There is insufficient evidence to support the claim that the standard deviation of the instruments is less than 0.00002 millimeters.

ii) p_v= P(\chi^2_{7}

Step-by-step explanation:

s=0.00001 represent the sample standard deviation

\alpha =0.01 represent the significance level for the test

\sigma_o =0.00002 represent the value that we want to test

n=8 represent the sample size

A chi-square test can be used to test "if the standard deviation of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test".

Null and alternatve hypothesis

The system of hypothesis on this case would be given by:

Null Hypothesis: \sigma \geq 0.00002

Alternative Hypothesis: \sigma

The statistic to test this is given by:

T=(n-1)(\frac{s}{\sigma_0})^2   (1)

Part i) Calculate the statistic

If we replace into formula (1) we got this:

T=(8-1)(\frac{0.00001}{0.00002})^2 =1.75   (1)

The critical region for a for a lower one-tailed alternative is given by

T< \chi^2_{1-\alpha/2,N-1}

The degrees of freedom are given by

df=n-1=8-1=7

And if we use the Chi Square distribution with 7 degrees of freedom we see that \chi^2_{1-0.01/2,7}=1.239

And our critical region would be T< 1.239 so on this case we can conclude that we fail to reject the null hypothesis. So it's not enough evidence to conclude that the population standard deviation is less than 0.00002 mm.

Part ii) Calculate the p value

In order to calculate the p value we can do this:

p_v= P(\chi^2_{7}

If we compare this value with the significance level (0.01) we see that p_v>\alpha

This agrees with the conclusion since when the p values is greater than the significance level we FAIL to reject the null hypothesis, same conclusion as part i).

7 0
3 years ago
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