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Ilya [14]
4 years ago
5

Round 34,514 to the nearest thousand

Mathematics
2 answers:
svet-max [94.6K]4 years ago
5 0

Answer:

35,000

Step-by-step explanation:

PilotLPTM [1.2K]4 years ago
5 0
35,000. remember if it’s anything above 500, round up. anything below, you’ll typically round down.
You might be interested in
Eliza started her savings account with $100. Each month she deposits $25 into her account. Determine the average rate of change
Afina-wow [57]
First, lets create a equation for our situation. Let x be the months. We know four our problem that <span>Eliza started her savings account with $100, and each month she deposits $25 into her account. We can use that information to create a model as follows:
</span>f(x)=25x+100
<span>
We want to find the average value of that function </span>from the 2nd month to the 10th month, so its average value in the interval [2,10]. Remember that the formula for finding the average of a function over an interval is: \frac{f(x_{2})-f(x_{1})}{x_{2}-x_{1} }. So lets replace the values in our formula to find the average of our function:
\frac{25(10)+100-[25(2)+100]}{10-2}
\frac{350-150}{8}
\frac{200}{8}
25

We can conclude that <span>the average rate of change in Eliza's account from the 2nd month to the 10th month is $25.</span>
6 0
3 years ago
What is <img src="https://tex.z-dn.net/?f=4%5Csqrt%7B16%7D" id="TexFormula1" title="4\sqrt{16}" alt="4\sqrt{16}" align="absmiddl
monitta
The square root of 16 is 4, so 4 times 4 equals 16

Your answer is 16 :)
3 0
2 years ago
Please help with 6 and 7
Maru [420]

Answer:

6a) i- 2hrs 36mins  ii- 3hrs 12mins

b) car A≈ 76.9km/h  car B≈ 62.5km/h

c)------

7a) 35km

b) car A=75km  car B=60km

c) 30km

d) car A≈36mins  car B≈48mins

Step-by-step explanation:

6a) Using the graph follow the lines until they finish then go downwards until you get to the x-axis. The x-axis is going up by 12mins for each square.

b) Using the answer from a, you divide 200km by the time.

For car A 2hrs 36mins becomes 2.6 because 36mins/60mins=0.6

∴ car A: 200/2.6≈ 76.92km/h

For car B 3hrs 12mins becomes 3.2 because 12mins/60mins=0.2

∴ car B: 200/3.2≈ 62.5km/h

7a) Using the graph go down from where the line of car A finished to meet car B. The y-axis is going up by 5km for each square.

b) Starting from the x-axis at 1 hour go upwards to see where you meet the car B line (60km) and car A line(75km). (sorry if that does not really make sense).

c) Difference from car A line to car B:

155km-125km=30km

d) Going across from 50km meet car A line and go down to see it has been travelling for approx. 36mins. Then continue across to car B line, go down to see it reached 50km at approx. 48mins.

Hope this helps.

5 0
4 years ago
Help pls this is for my math test.
Stells [14]

Answer:

D is the answers for the question

Step-by-step explanation:

please mark me as brainlest

5 0
3 years ago
Read 2 more answers
Hii! please help asap. i’ll give brainliest
charle [14.2K]

Answer:

I think it would be 3500 if not i am sorry hope this helps

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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