5 hundreds x 10 = 50 hundreds = 5000
Now in the above solution we can see that the multiple of 5 hundreds with a 10 gives a result of 50 hundreds. If we want ot simplify it further then we can write
500 x 10 = 50 x 100 = 5000
Given that the scale readings of the laboratory scale is normally distributed with an unknown mean and a standard deviation of 0.0002 grams.
Part A:
If the weight is weighted 5 times and the mean weight is 10.0023 grams, the 98% confidence interval for μ, the true mean of the scale readings is given by:

Thus, we are 98% confidence that the true mean of the scale readings is between 10.0021 and 10.0025.
Part B:
To get a margin of error of +/- 0.0001 with a 98% confidence, then

Therefore, the number of <span>measurements that must be averaged to get a margin of error of ±0.0001 with 98% confidence is 22.</span>