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Sunny_sXe [5.5K]

3 years ago

8

f the original price of a table is p and the sale price of the table is p−0.2p, which other expression represents the sale price

of the table?

1 answer:

Sphinxa [80]3 years ago

6 0

Answer:

0.2p is the correct

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a line passes through the point (-9,7) and has a slope of -4/3 write an equation in point slope form for this line

DENIUS [597]

The answer would be: Y= -4/3x - 5

5 0

3 years ago

Please help I don’t wanna add a bunch of points Bc nobody is helping me I’m just wasting them.

Ede4ka [16]

Answer:Cross multiply and solve for x.

x/6 = 5/1.25

let the height of building be h ft

h/6 = 60/15

h = 6(60/15) = 24

the building is 24 ft high

Step-by-step explanation:

Well first let’s covert the ft to in- 5ft is 60 in and 6ft is 72 in. Then we want to set up 2 fractions based on height and shadow, so we have 60/15=x/72 (we put x because that’s what we’re trying to find). Then we do cross multiplication so now we have 15x=4320. We divide 15, so now we have 4320/15=288. So the building is 288 in tall or 24ft tall! Glad to help! :)

3 0

3 years ago

Sandile bought 58 pies, each pie cost R68 each. estimate the total price of the pies..

podryga [215]

Answer: 3944
All you have to do is multiply 58 x 68 to get the answer.
( hope this helped! )

5 0

2 years ago

4162 to 3 significant figures

butalik [34]

Hey there Altagraciasouth :)

Significant Figure Question:

**Question 4162 to 3 SF

Explanation:

We first have to look for the third number in 4162. That would be 62!

So we round 62 to the nearest ten. Which gives us 60!

**Answer: 4160

Hope this helped :)

8 0

3 years ago

At a certain high school, 15 students play stringed instruments and

Aleks [24]

Answer:

<em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.

Step-by-step explanation:

Given that:

Number of students who play stringed instruments, N(A) = 15

Number of students who play brass instruments, N(B) = 20

Number of students who play neither, N( $A \cup B$ )' = 5

<u>To find:</u>

The probability that a randomly selected students plays both = ?

<u>Solution:</u>

Total Number of students = N(A)+N(B)+N( $A \cup B$ )' =15 + 20 + 5 = 40

(As there is no student common in both the instruments we can simply add the three values to find the total number of students)

As per the venn diagram, no student plays both the instruments i.e.

$N(A\cap B) =0$

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A\cap B) = \dfrac{N(A\cap B)}{N(U)}\\\Rightarrow \dfrac{0}{40}\\\Rightarrow P(A\cap B) = 0$

So, <em>0</em> is the probability that a randomly selected student plays both a stringed and a brass instrument.

5 0

3 years ago