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3 years ago

Could someone help me solve the inequality? |x-18| > or = to 6

2 answers:

4 0

$|x-18|\geq6\iff x-18\geq6\ \vee\ x-18\leq-6\ \ \ |add\ 18\ to\ both\ sides\\\\x\geq24\ \vee\ x\leq12\\\\x\in(-\infty;12]\ \cup\ [24;\ \infty)$

xeze [42]3 years ago

3 0

$|x-18|\geq6\\
x-18\geq 6 \vee x-18\leq-6\\
x\geq24 \vee x\leq 12\\
x\in(-\infty,12\rangle\cup\langle24,\infty)$

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