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nydimaria [60]
3 years ago
13

Could someone help me solve the inequality? |x-18| > or = to 6

Mathematics
2 answers:
dusya [7]3 years ago
4 0
|x-18|\geq6\iff x-18\geq6\ \vee\ x-18\leq-6\ \ \ |add\ 18\ to\ both\ sides\\\\x\geq24\ \vee\ x\leq12\\\\x\in(-\infty;12]\ \cup\ [24;\ \infty)
xeze [42]3 years ago
3 0
|x-18|\geq6\\
x-18\geq 6 \vee x-18\leq-6\\
x\geq24 \vee x\leq 12\\
x\in(-\infty,12\rangle\cup\langle24,\infty)
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Distribute 3(5x -1)<br> thank you&lt;3.
AysviL [449]

Answer:

(3x5)+(3x-1) = 15+(-3)= 12

Step-by-step explanation:

There you go :)

7 0
3 years ago
Read 2 more answers
Angela is going on vacation to Mexico. She needs to buy new shirts for her trip. She buys 10 new shirts that cost her a total of
vivado [14]
Angela purchased 4 casual shirts and 6 dressy shirts.

$25 × 6 = $150
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$150 + $72 = $222

hope this helped :)
8 0
4 years ago
Best known for its testing program, ACT, Inc., also compiles data on a variety of issues in education. In 2004 the company repor
GarryVolchara [31]

Answer:

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

Step-by-step explanation:

Check for conditions

For this case in order to use the normal distribution for this case or the 68-95-99.7% rule we need to satisfy 3 conditions:

a) Independence : we assume that the random sample of 400 students each student is independent from the other.

b) 10% condition: We assume that the sample size on this case 400 is less than 10% of the real population size.

c) np= 400*0.74= 296>10

n(1-p) = 400*(1-0.74)=104>10

So then we have all the conditions satisfied.

Solution to the problem

For this case we know that the distribution for the population proportion is given by:

p \sim N(p, \sqrt{\frac{p(1-p)}{n}})

So then:

\mu_p = 0.74

\sigma_p =\sqrt{\frac{0.74(1-0.74)}{400}}=0.0219

The empirical rule, also referred to as the three-sigma rule or 68-95-99.7 rule, is a statistical rule which states that for a normal distribution, almost all data falls within three standard deviations (denoted by σ) of the mean (denoted by µ). Broken down, the empirical rule shows that 68% falls within the first standard deviation (µ ± σ), 95% within the first two standard deviations (µ ± 2σ), and 99.7% within the first three standard deviations (µ ± 3σ).

\mu_p -\sigma_p = 0.74-0.0219=0.718

\mu_p +\sigma_p = 0.74+0.0219=0.762

68% of the rates are expected to be betwen 0.718 and 0.762

\mu_p -2*\sigma_p = 0.74-2*0.0219=0.696

\mu_p +2*\sigma_p = 0.74+2*0.0219=0.784

95% of the rates are expected to be betwen 0.696 and 0.784

\mu_p -3*\sigma_p = 0.74-3*0.0219=0.674

\mu_p +3*\sigma_p = 0.74+3*0.0219=0.806

99.7% of the rates are expected to be betwen 0.674 and 0.806

5 0
3 years ago
Help me please...........:)
BabaBlast [244]

Answer:

4/3

Step-by-step explanation:

3 0
3 years ago
CAN SOMEONE PLS ANSWER THIS ILL REALLY APPREICIATE IT
GrogVix [38]
The answer would be -2! :)
3 0
4 years ago
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