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lakkis [162]
3 years ago
11

What is 3.98 X10 raise to power 10 In standard form

Mathematics
2 answers:
Artist 52 [7]3 years ago
4 0
39,800,000,000 seems about right.
bonufazy [111]3 years ago
3 0
39,800,000,000 is the correct answer, I believe.
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Use the grouping method to factor x^3+x^2+5x+5
serious [3.7K]

Answer:

a

Step-by-step explanation:

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3 years ago
What is √36ab^4c^5 ?
Zanzabum
You'll need to use parentheses to indicate what is under the first radical sign and what is not.  Did you mean radical(36a) or just radical 36?

I will assume that you meant radical(36a).

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3 0
3 years ago
How much times can 3 go into 78
Sedbober [7]

Answer:

26

Step-by-step explanation:

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4 0
2 years ago
Read 2 more answers
Find the indicated sum.
OlgaM077 [116]

Answer:

B. 70

Step-by-step explanation:

We have the sum given by \sum_{i=1}^{5}(i+11)).

Now, we open the summation by substituting the values of 'i',

i.e. \sum_{i=1}^{5}(i+11)). = (1+11) + (2+11) + (3+11) +(4+11) +(5+11)

i.e. \sum_{i=1}^{5}(i+11)). = 12 + 13 + 14 + 15 + 16

i.e. \sum_{i=1}^{5}(i+11)). = 70.

Hence, the sum of \sum_{i=1}^{5}(i+11)). is 70.

So, option B is correct.

6 0
4 years ago
What is the distance between the following coordinates? Show work.
miss Akunina [59]

Answer:

\huge{ \boxed{ \bold{ \tt{2 \sqrt{26}}}  \:  \: \text{units} } }

<h3>♁ Question :</h3>
  • Find the distance between ( 5 , -6 ) and ( 3 ,4 ).

<h3>♁ Step by step explanation:</h3>

Let the points be A and B. Now,

  • Let, A ( 5 , -6 ) ⇢ ( x₁ , y₁ )
  • Let, B ( 3 , 4 ) ⇢ ( x₂ , y₂ )

Use the distance formula to determine the distance between A ( 5 , -6 ) and B ( 3 , 4 ).

\boxed{ \underline{ \sf{distance =  \sqrt{ {(x2 - x1)}^{2}  +  {(y2 - y1)}^{2} } }}}

Substitute the actual value of the points into the distance formula and then simplify.

\dashrightarrow{ \sf{ \sqrt{ {(3 - 5)}^{2} +  {(4 - ( - 6))}^{2}  } }}

Remember : The positive and negative integer are always subtracted but posses the sign of the bigger integer.

\dashrightarrow{ \sf{ \sqrt{ {( - 2)}^{2}  +  {(4 - ( - 6))}^{2} } }}

Remember : ( - ) × ( - ) = ( + )

\dashrightarrow{ \sf{ \sqrt{ {( - 2)}^{2} +  {(4 + 6)}^{2}  } }}

Add the numbers : 4 and 6

\longrightarrow{ \sf{ \sqrt{ {( - 2)}^{2}  +  {(10)}^{2} } }}

Evaluate the power

\longrightarrow{ \sf{ \sqrt{4 + 100}}}

Add the numbers : 4 and 100

\dashrightarrow{ \sf{ \sqrt{104}}}

\dashrightarrow{ \boxed{ \sf{2 \sqrt{26} }}} units

Therefore , The distance between ( 5 , -6 ) and ( 3 , 4 ) is \sf{2 \sqrt{26}} units .

And we're done!

Hope I helped!

Have a wonderful time ! シ

~TheAnimeGirl

5 0
3 years ago
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