Answer:
41.4
Step-by-step explanation: Since this isn't a right triangle and you're given side side side (SSS), you need the Law of Cosines.
cos(c) = (a^2 + b^2 - c^2)/2ab
(100+144-64)/2*12*10
cos(c) = 180/240
multiply both sides of the equation by cos^-1 to get ride of cos:
cos^-1(cos(c)) = cos^-1(180/240)
c = 41.4
36.08 = 8.8t
The distance is a positive because it shows the total distance traveled
36.08 = 8.8t
4.1=t
The formula for a falling object is
v = u +gt
where
u = initial velocity (=0 for a falling object)
g = acceleration due to gravity, 32.2 ft/s²
t = time, s
In terms of distance fallen,
v² = u² + 2gh
where h = distance fallen, ft.
Because h = 23 ft and u = 0, therefore
v² = 2*32.2*23 = 1481.2
v = 38.486 ft/s
Answer: 28.49 ft/s (nearest hundredth)
Answer:
x ≈ 1.9087
Step-by-step explanation:
We don't know what methods you learned in class, but here's one way to solve the equation.
Make x the exponent of a constant:
5^(x+2) = 3^(3x)
(5^x)(5^2) = (3^3)^x
25(5^x) = 27^x
Put the powers all on one side of the equation and everything else on the other side.
25 = (27^x)/(5^x) = (27/5)^x = 5.4^x
Take logarithms.
log(25) = x·log(5.4)
x = log(25)/log(5.4)
x ≈ 1.9087
