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skad [1K]
3 years ago
5

A rectangular gift box measures 8 inches by 10 inches by 3 inches. what is the surface area?

Mathematics
2 answers:
mestny [16]3 years ago
8 0
8 x 10 = 80 inches squared (one side)
3 x 8 = 24 inches squared (one side)
3 x 10 = 30 inches squared (one side)
80 + 24 + 30 = 134 inches squared (three sides)
Double that for all 6 sides. 2 x 134 = 268 square inches.
The answer is D.
nevsk [136]3 years ago
3 0
SA = 2<span>(<span><span><span>wl</span>+<span>hl</span></span>+<span>hw</span></span><span>)

SA = </span></span>2<span>(<span><span><span>(3)(10)</span>+<span>(8)(10)</span></span>+<span>(8)(3)</span></span><span>)

Multiply:

SA = 2(30 + 80 + 24)

Add:

SA = 2(134)

Multiply:

SA = 268</span></span>
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A random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specime
MrRissso [65]

Answer:

We conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

We conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

Step-by-step explanation:

We are given a random sample of soil specimens was obtained, and the amount of organic matter (%) in the soil was determined for each specimen;

1.10, 5.09, 0.97, 1.59, 4.60, 0.32, 0.55, 1.45, 0.14, 4.47, 1.20, 3.50, 5.02, 4.67, 5.22, 2.69, 3.98, 3.17, 3.03, 2.21, 0.69, 4.47, 3.31, 1.17, 0.76, 1.17, 1.57, 2.62, 1.66, 2.05.

Let \mu = <u><em>true average percentage of organic matter</em></u>

So, Null Hypothesis, H_0 : \mu = 3%      {means that the true average percentage of organic matter in such soil is 3%}

Alternate Hypothesis, H_A : \mu \neq 3%      {means that the true average percentage of organic matter in such soil is something other than 3%}

The test statistics that will be used here is <u>One-sample t-test statistics</u> because we don't know about the population standard deviation;

                         T.S.  =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean percentage of organic matter = 2.481%

             s = sample standard deviation = 1.616%

            n = sample of soil specimens = 30

So, <u><em>the test statistics</em></u> =  \frac{2.481-3}{\frac{1.616}{\sqrt{30} } }  ~ t_2_9

                                     =  -1.76

The value of t-test statistics is -1.76.

(a) Now, at 10% level of significance the t table gives a critical value of -1.699 and 1.699 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics doesn't lie within the range of critical values of t, so we have <u><em>sufficient evidence to reject our null hypothesis</em></u> as it will fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is something other than 3% at 10% significance level.

(b) Now, at 5% level of significance the t table gives a critical value of -2.045 and 2.045 at 29 degrees of freedom for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of t, so we have <u><em>insufficient evidence to reject our null hypothesis</em></u> as it will not fall in the rejection region.

Therefore, we conclude that the true average percentage of organic matter in such soil is 3% at 5% significance level.

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3 years ago
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Answer:

n+5×4-7

Step-by-step explanation:

6 0
2 years ago
Which shows a correct order to solve this story problem? Peter bought 3 biscuits for $1.59 each and 3 sausages for $2.50 each at
IceJOKER [234]
Since he bought more than one of each, he needs to find the total cost of the biscuits and sausage first.

 The correct answer should be:

<span>B. Step 1: Calculate the price of 3 biscuits. Step 2: Calculate the price of 3 sausages. Step 3: Add the total amounts from Steps 1 and 2 to the amount of the tip. Step 4: Subtract that total amount from $25.</span>
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natta225 [31]

Answer:

the mean is 57.5 the median is 44.5 and the mode is 47

Step-by-step explanation:

the mode is 47 cuz it appeared twice. the median is 57.5 bc 47+147+24+47+38+42=345 and 345/6 is 57.5

7 0
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1) A population of genetically modified
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This is a linear equation or y=mx+c. Where y is the number of mosquitos at a particular month and x is the number of months. We know the initial population of the mosquitoes is c=20. They population doubles every month so this is the gradient, m=2. Therefore the equation for the growth of the mosquito population is:
y = 2x + 20.

So after x= 10 months the mosquito population will be,
y=2(10)+20= 40.

There will be 40 mosquitoes after ten months.
7 0
2 years ago
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