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ankoles [38]
2 years ago
11

Can someone help me with this question if two figures are similar but not congruent, how are they alike, and how are they differ

ent?
Mathematics
1 answer:
kenny6666 [7]2 years ago
3 0
Two figures are similar if they have the same shape but not necessarily the same size although they are the same shape they are different sizes
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What is the value of the expression below when z=7 6z-2
horsena [70]

Answer:

the answer is 40

Step-by-step explanation:

U multiply then subtract.

6 0
2 years ago
Please answer this question right now ​
Westkost [7]

Answer:

6) c

7) d

Step-by-step explanation:

6) 25 + 15= 40

40+35=75

Php. 75

7) 29•3=87

150-87=63

Php. 63

Hope this helps!

6 0
3 years ago
The length of the hypotenuse of a right triangle is 50 inches. Determine the length of the legs if each leg is the same length.
algol13

Answer:

  25√2 ≈ 35.36 inches

Step-by-step explanation:

The Pythagorean theorem can be used to find the leg length for the given conditions. It tells you the relation between legs a, b, and hypotenuse c is ...

  c² = a² +b²

If a=b, and c=50, this becomes ...

  50² = a² +a²

  1250 = a² . . . . divide by 2

  25√2 = a . . . . take the square root

The length of each leg is 25√2 ≈ 35.36 inches.

4 0
2 years ago
Write (8a-^3) -2/3 in simplest form
Anna71 [15]

(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}

<em><u>Solution:</u></em>

<em><u>Given that,</u></em>

(8a^{-3})^{\frac{-2}{3}

We have to write in simplest form

<em><u>Use the following law of exponent</u></em>

(a^m)^n = a^{mn}

Using this, simplify the given expression

(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^{ -3 \times \frac{-2}{3}}\\\\Simplifying\ we\ get\\\\(8a^{-3})^{\frac{-2}{3}} = 8^{\frac{-2}{3}} \times a^2\\\\We\ know\ that\ 8 = 2^3\\\\Therefore\\\\(8a^{-3})^{\frac{-2}{3}} =2^3^{\frac{-2}{3}} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} =2^{-2} \times a^2\\\\(8a^{-3})^{\frac{-2}{3}} = \frac{a^2}{4}

Thus the given expression is simplified

8 0
3 years ago
Please help me! Given (x+a)(x+b) = x^2+x-12, what is the value of a^2+b^2
Sonja [21]
(x + 4) (x - 3)
a = 4
b = -3

a^2 + b^2 = ...
= 4^2 + (-3)^2
= 16 + 9
= 25
4 0
3 years ago
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