Answer:
The proof is explained step-wise below :
Step-by-step explanation :
For better understanding of the solution see the attached figure :
Given : ABCD is a Parallelogram ⇒ AB ║ DC and AD ║ BC
Now, F lies on the extension of DC. So, AB ║ DF
To Prove : ΔABE is similar to ΔFCE
Proof :
Now, in ΔABE and ΔFCE
∠ABE = ∠FCE ( alternate angles are equal )
∠AEB = ∠FEC ( Vertically opposite angles )
So, by using AA postulate of similarity of triangles
ΔABE is similar to ΔFCE
Hence Proved.
<span>-8(5r+6)+9(6r+3)
= -40r - 48 + 54r + 27
= 14r - 21</span>
The answer to your question is option b because opposite angles in a quadrilateral are equal to one another
First, u do -9+8x-4+8
Then, U simplify. The answer is 8x-5
ANSWER: Plane dropped 6097 feet in altitude.
BECAUSE: An airplane is at point A from where it continued to descend by 30° for an approximate distance of 2 miles
∠ACB = Angle of descent = 30°
Distance BC = 2 miles
Let the plane dropped the altitude = h miles
Now tan 30° =
h = 1.155 miles
h ≈ 1.16 miles
Since 1 mile = 5280 feet
1.15 miles = 5280×1.16 feet
= 6097 feet
Therefore, the plane dropped by 6097 feet vertically.
