<u>Answer:</u>
<u>Step-by-step explanation:</u>
------------(1) (given)
-------------(2) (given)
so,
f(x) = h(g(x)) (given)
= -----(from (1) and (2))
⇒-----(taking g(x) = k)
⇒ is the function.
If f(x) and its inverse function,f-1(x), are both plotted on the same coordinate plane, where is their point of intersection?
2 answers:
Consider f, such that f(x)=y, where x is in the Domain of f, and y is in the Range of f.
Let f(a)=b. So, (a, b) is in the graph of f.
The inverse function of f,
(if exists) is such that if f(x)=y, then 
.
So if (a, b) is a particular point in the graph of f, then (b, a) is a point in the graph of.
A point where they intersect is a point where (a, b)=(b, a), that is a=b. Among our choices, only (2, 2) satisfies this condition.
Answer: (2, 2)
Let f(a)=b. So, (a, b) is in the graph of f.
The inverse function of f,
So if (a, b) is a particular point in the graph of f, then (b, a) is a point in the graph of
A point where they intersect is a point where (a, b)=(b, a), that is a=b. Among our choices, only (2, 2) satisfies this condition.
Answer: (2, 2)
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The solutions to the homogeneous equation are:
Finally you need the constant term in "cy" to equal 'd' to satisfy the particular solution.
Answer:
y=
Step-by-step explanation:
I used an online graphing calculator and process of elimination...