If f(x) and its inverse function,f-1(x), are both plotted on the same coordinate plane, where is their point of intersection?
2 answers:
Consider f, such that f(x)=y, where x is in the Domain of f, and y is in the Range of f.
Let f(a)=b. So, (a, b) is in the graph of f.
The inverse function of f,
(if exists) is such that if f(x)=y, then 
.
So if (a, b) is a particular point in the graph of f, then (b, a) is a point in the graph of.
A point where they intersect is a point where (a, b)=(b, a), that is a=b. Among our choices, only (2, 2) satisfies this condition.
Answer: (2, 2)
Let f(a)=b. So, (a, b) is in the graph of f.
The inverse function of f,
So if (a, b) is a particular point in the graph of f, then (b, a) is a point in the graph of
A point where they intersect is a point where (a, b)=(b, a), that is a=b. Among our choices, only (2, 2) satisfies this condition.
Answer: (2, 2)
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Answer:
A. SAS
Step-by-step explanation:
In the figure attached, the triangles are shown.
The Side Angle Side postulate (SAS) states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then these two triangles are congruent.
In this case, the two sides of triangle ABC are AC and BC and the included angle is ∠C, which are congruent with sides BD and BC and the included angle ∠B from triangle BCD
