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Nookie1986 [14]
3 years ago
8

Scatter plots & trend lines is there a easier way to do this?

Mathematics
1 answer:
ira [324]3 years ago
7 0

Answer:

23

Step-by-step explanation:

Using the best fit equation y = 1.5x - 1

with x = 16 ( number of years since 2000 ), then

y = (1.5 × 16) - 1 = 24 - 1 = 23

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4(x - 2) = 2x + 3(x - 5)
yaroslaw [1]

Answer:

x=7

Step-by-step explanation:

  1. 4(x-2) = 2x+3(x-5)
  2. 4x-8 = 2x+3x-15
  3. 4x-8 = 5x -15
  4. -x = -7
  5. x = 7

8 0
3 years ago
17/6 + 4/3 fractions
polet [3.4K]

Answer:

25/6

Step-by-step explanation:

I multiplied 4/3 by 2, so the new fraction is 8/6. You add 17/6 with 8/6, and you get 25/6. I hope you understand.

8 0
3 years ago
Find x if Q is the midpoint of PR, PQ-19, and PR 8x + 14<br>a. 14. B7<br>C 3. D5​
Sonja [21]

Answer:

Step-by-step explanation:

If Q is the midpoint of PR and PQ is 19, that means that QR is also 19 and the total length of PR is 38. Therefore,

PQ + QR = PR and

19 + 19 = 8x + 14 and

38 = 8x + 14 and

24 = 8x so

x = 3

Your choice is C

3 0
3 years ago
PLSSSS HELP ME WITH THIS QUESTION!!!
AysviL [449]

Given,  

∠AOE = 30°

∠DOB = 40°

So, ∠EOD = 180 - (30+40)           [angles on a straight line]

                =  180 - 70

                =  110

∠EOD = ∠COF                             [ vertically opposite angle]

∴ ∠COF = 110°

7 0
3 years ago
Read 2 more answers
I will give BRAINLIEST.
timama [110]

You would know that

\displaystyle\lim_{x\to\pm1}f(x)=1

It follows from the sandwich/squeeze theorem: for instance,

x^4 \le f(x) \le x^2 \implies \displaystyle\lim_{x\to-1}x^4 \le \lim_{x\to-1}f(x) \le \lim_{x\to-1}x^2 \implies 1 \le \lim_{x\to-1}f(x) \le 1 \\\\ \implies \lim_{x\to-1}f(x)=1

3 0
3 years ago
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