Answer:
Answer is 0.5
Step-by-step explanation:
The text implies that the number of traffic accidents determines the number of ambulances required on the road. Hence, 1 traffic accident requires 1 ambulance.
The time slot and time of day remain same in both the text and the question.
The average or mean number of accidents is 1.1
QUESTION: What then is the probability that there is need for exactly 2 ambulances on that road and in that time frame?
In other words, what is the probability that there'll be 2 accidents on that road and in that time frame?
Since the mean number of accidents is 1.1, 2 is above the mean.
Probability of 1.1 accidents is 1, since that's the mean (expected value).
Probability of 2 accidents is 1/2 which is = 0.5
You would time the denominator by 3 so 11*3 would be 33 then times the numerator by the same so 6*3 soot would be 18/33
<h2>
<em><u>My</u></em><em><u> </u></em><em><u>equation</u></em><em><u> </u></em></h2>
<em>f</em><em>(</em><em>x</em><em>=</em><em>x</em><em>^</em><em>2</em><em> </em><em>is</em><em> </em><em>30</em><em> </em><em>and</em><em> </em><em>g</em><em>(</em><em>x</em><em>)</em><em> </em><em>=</em><em>4 1</em><em> </em><em> </em><em>is</em><em> </em><em>50</em><em>.</em><em>1</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>helps</em><em> </em><em>#brainliestbunch</em><em> </em><em>=</em><em>)</em><em> </em>
Answer:
39/18 = 13/6 = 2 1/6
Step-by-step explanation:
factors are 1,2,3,6,9,18
so the reciprocals are
1/1, 1/2, 1/3, 1/6, 1/9, 1/18
when added the sum is 39/18 or 2 1/6
