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3 years ago

PLEASE HELP ASAP! I WILL MARK AS BRAINLIEST!!

Mathematics

2 answers:

statuscvo [17]3 years ago

8 0

THE AREA IS 20 UNITS BECAUSE IF YOU DIVIDE IT INTO 2 SQUARES, THE FIRST ONE IS 4*3=12. THE SECOND ONE IS 2*4=8.
12+8=20.

HOPE THIS HELPED☺☺

ahrayia [7]3 years ago

8 0

Answer:

Step-by-step explanation:

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What is the difference 6 - 3 2/5 =

Luba_88 [7]

It depends on what the question looks like. If it looks like this:
(6-3)(2/5)=
(3)(0.4)=
1.2

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4 years ago

Help ASAP will mark Brainly to who ever answers 1st

ch4aika [34]

Answer:

Step-by-step explanation:

the bottom left is the answer. I hope this helps.

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2 years ago

Y-intercept is 100 and slope is 5. Partner gave example: Younger brother had 100 small building blocks, but lost 5 of them every

ArbitrLikvidat [17]

Since he lost 5 every month, it should be that the slope is -5, not 5, he is not gaining 5 every month

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3 years ago

The vertex of this parabola is at (-2, 5) (opens upward)

Rzqust [24]

Answer:

b. y = 3(x+2)^2 + 5

Step-by-step explanation:

The vertex form of a parabola is

y = a(x - h)^2 + k where (h, k) is the vertex.

Here h = -2 and k = 5 so the following could be the required equation\;

y = 3(x+2)^2 + 5

7 0

3 years ago

Expanding Logarithmic Expressions In Exercise, use the properties of logarithms to rewrite the expression as the sum, difference

kicyunya [14]

Answer:

$\\ ln(x^2) - ln(x^2 + 1)$ .

For values of x>0, it can be rewritten as $\\ 2ln(x) - ln(x^2 + 1).$

Step-by-step explanation:

For the expression:

$\\ ln(\frac{x^2}{x^2 + 1})$

We can apply this logarithmical property: $\\ ln(\frac{x}{y}) = ln(x) - ln(y).$

Then,

$\\ \frac{x^2}{x^2 + 1} = ln(x^2) - ln(x^2 + 1).$

If we assume values of <em>x </em>> 0 (non negative values for x), then the expression could be rewritten as follows:

$\\ \frac{x^2}{x^2 + 1} = ln(x^2) - ln(x^2 + 1) = 2 ln(x) - ln(x^2 + 1)$ , since $\\ ln(x^{n}) = n*ln(x).$

We have to remember that <em>domain</em> (all possible values x) for logarithmic function is for all x > 0, or mathematically expressed as:

Domain: $\\ {x | x \in R, x > 0}$

8 0

3 years ago