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german
3 years ago
13

What is the value of the expression 2.6 x 10 to the power of 9 divided by 1.3 x 10 to the power of 2

Mathematics
1 answer:
bazaltina [42]3 years ago
7 0
(2.6 * 10^9) / (1.3 * 10^2) =
(2.6 / 1.3) * (10^9) / (10^2) =
2 * 10^7 or 20,000,000 <===
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8. The difference between two numbers is 14. If 1/3of the larger number is subtracted from the smaller number, the
Serjik [45]

Answer:

The values of the 2 numbers whose sum is 13 and difference is 3, are: {8 ; 5}.

Step-by-step explanation:

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3 years ago
Multi step equation that equal 27 when solved
Ksenya-84 [330]
Sample Equation:  3x - 3 = 27

Multiple step:

3x    -  3  =    27
 <u>       + 3       +3</u>  Step1. Remove the -3 by adding 3 to both sides
3x            =   30
<u>÷3                ÷ 3</u>  Step2. Remove the multiplicand 3 by dividing both sides by 3
x              =  10

To check: substitute x by its value

3x - 3 = 27
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6 0
3 years ago
Using t=tanx/2, write an expression for sinx and cosx in terms of t.
Dafna11 [192]

Assume 0 < <em>x</em>/2 < <em>π</em>/2. Then

tan²(<em>x</em>/2) + 1 = sec²(<em>x</em>/2)   ===>   sec(<em>x</em>/2) = √(1 - tan²(<em>x</em>/2))

===>   cos(<em>x</em>/2) = 1/√(1 - tan²(<em>x</em>/2))

===>   cos(<em>x</em>/2) = 1/√(1 - <em>t</em> ²)

We also know that

sin²(<em>x</em>/2) + cos²(<em>x</em>/2) = 1   ===>   sin(<em>x</em>/2) = √(1 - cos²(<em>x</em>/2))

Recall the double angle identities:

cos(<em>x</em>) = 2 cos²(<em>x</em>/2) - 1

sin(<em>x</em>) = 2 sin(<em>x</em>/2) cos(<em>x</em>/2)

Then

cos(<em>x</em>) = 2/(1 - <em>t</em> ²) - 1 = (1 + <em>t</em> ²)/(1 - <em>t</em> ²)

sin(<em>x</em>) = 2 √(1 - 1/(1 - <em>t</em> ²)) / √(1 - <em>t</em> ²) = 2<em>t</em>/(1 - <em>t</em> ²)

7 0
2 years ago
Given that y=x^(1/3) , use calculus to determine an approximate value for ∛8030
Alex777 [14]
F(x) = x^(1/3)
f(8000) = 8000^(1/3) = 20

f'(x) = 1/3 * x^(-2/3)
f'(x) = 1/(3x^(2/3))
f'(8000) = 1/(3*8000^(2/3)) = 1/(3*400) = 1/1200

Linear approximation for f(x) about x = 8000
L(x) = f(8000) + f'(8000) (x−8000)
L(x) = 20 + 1/1200 (x−8000)

8030^(1/3) ≈ L(8030)
= 20 + 1/1200 (8030−8000)
= 20 + 30/1200
= 20 + 1/40
= 20.025
8 0
3 years ago
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