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3 years ago

1. x-1 / 6 =2 2. -3= k-5 / 16 Find x and k

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

7 0

Answer:

x = 13

k = 43

Step-by-step explanation:

$\frac{x-1}{6} = 2$

Multiply both sides by 6

$\frac{6}{1}$ × $\frac{x-1}{6} = 2$ × $\frac{6}{1}$

$x - 1 = 12$

Add one to each side

$x = 13$

$-3 = \frac{k-5}{16}$

Multiply both sides by 16

$\frac{16}{1}$ × $-3 = \frac{k-5}{16}$ × $\frac{16}{1}$

$k - 5 = -48$

Add 5 to each side

$k = 43$

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Please help me..........<br><br>only 32,and 33

kupik [55]

Answer:

Step-by-step explanation:

Step 1 : Draw PQ = 6cm

Step 2 : Construct 60 degree at Q. [Given PQR = 60=> Q = 60 ]

Step 3 : Take 5 cm on compass and mark 5cm on the 60 degree

line constructed at Q.

Step 4 : The arc of 5cm and 60 degree line meets is the point R.

[Given QR = 5cm ]

Step 5 : Given PQ || SR so construct a 120° at R ,

because ∠PQR and ∠QRS are supplementary angle.

[ ∠PQR + ∠QRS = 60 + 120 = 180° ]

Step 6 : At P , take 6.5 cm on compass and mark on the line drawn in

Step 5, to get S. [ Given PS = 6.5 ]

Given adjacent sides : 4.8 and 4.2

And it is a rectangle.

Step 1 : construct AB = 4.8 cm

Step 2 :At A and B construct 90 degree

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Step 4 : Mark that as C and D respectively.

Step 5 : Join CD

8 0

3 years ago

To reach a vacation spot, the Jones family first traveled by plane and then drove the

navik [9.2K]

The distance flown by plane is 750 kilometers.

Step-by-step explanation:

Let,

Distance traveled by plane = x

Distance traveled by car = y

Total distance = x+y

According to given statement;

The distance by car was 125 kilometers less than the distance by plane.

y = x - 125 => x=y+125 Eqn 1

The total distance was 500 kilometers less than three times the distance traveled by car.

Total distance = 3y - 500

x+y=3y-500 Eqn 2

Putting value of x from Eqn 1;

$(y+125)+y=3y-500\\y+y+125=3y-500\\2y=3y-500-125\\2y-3y=-625\\-y=-625\\y=625$

Putting y=625 in Eqn 1

$x=625+125\\x=750$

The distance flown by plane is 750 kilometers.

Keywords: linear equations, substitution method

Learn more about linear equations at:

#LearnwithBrainly

3 0

3 years ago

What number must you add to complete the square x^-8x=39

notsponge [240]

Answer:

Given equation: $x^2-8x =39$

when we complete the square , we take half of the value of 8 , then square it, and added to the left sides, we get;

$x^2-8x+4^2 = 39 +4^2$

∵8 is the value $(\frac{8}{2})^2$

Notice that, we add this both sides so that it maintains the equality.

then;

$x^2-8x+4^2 = 39 +4^2$

$(x-4)^2 = 39 + 16$ [ $(a-b)^2 = a^2-2ab+b^2$ ]

Simplify:

$(x-4)^2 =55$

The number must be added to complete the square is, $4^2 = 16$

3 0

3 years ago

Read 2 more answers

1) Write a system of equations to describe the situation below, solve using any method, and

Aloiza [94]

This situation can be represented by

y = 33x + 223

y = 32x + 239

I still like substitution, so let’s plug in 33x + 223 into the second equation

33x + 223 = 32x + 239

Move the terms into appropriate sides

33x - 32x = 239 - 223

Combine like terms

x = 16

Then plug in x for any equation

y = 32(16) + 239

y = 751

Erin will have to swim 16 laps for a total of 751 meters

7 0

2 years ago

Which expression is equivalent to one over threep + 15? one over three(p + 45) one over three(p + 5) 3(p + 45) 3(p + 5)

elena-s [515]

Answer:

$\large\boxed{\dfrac{1}{3p+15}=\dfrac{1}{3(p+5)}}$

Step-by-step explanation:

"one over threep + 15":

$\dfrac{1}{3p+15}=\dfrac{1}{(3)(p)+(3)(5)}=\dfrac{1}{(3)(p+5)}=\dfrac{1}{3(p+5)}$

5 0

3 years ago

Read 2 more answers