Consider the polynomial function T(x)=2x(x-3)(x+1). What are the zeros of T(x)
1 answer:
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<h2>The first term of the given sequence (a) = 6561</h2>
Step-by-step explanation:
Let the first term = a and common difference = d
Given,
= 729 and
= 243
To find, the first term of the given sequence (a) = ?
We know that,
The nth term of a G.P.
The 3rd term of a G.P.
⇒ = 729 ..............(1)
The 4th term of a G.P.
⇒ = 243 ..............(2)
Dividing equation (2) by (1), we get
=
⇒
Put in equation (1), we get
= 729
⇒ = 729
⇒ a = 9 × 729 = 6561
∴ The first term of the given sequence (a) = 6561
Subtract
Factor
Factor out common term
refine:
true for all
hope this helps!