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MrRissso [65]
3 years ago
7

5z + 2 = 3z - 10Show your work and I will give you brainlist ​

Mathematics
1 answer:
yuradex [85]3 years ago
6 0

Answer:

z = -6

Step-by-step explanation:

5z + 2 = 3z - 10

Subtract 3z from both sides

2z + 2 = -10

Subtract 2 from both sides

2z = -12

Divide each side by 2

z = -6

So, the answer is z = -6

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Find an equivalent function for the following: <br><br> f(x) = 3(2)4x
n200080 [17]
Hi there!

To find an equivalent function for this function, we can just simplify it. 

f(x) = (6)4x

f(x) = 24x
is an equivalent function. 

Hope this helps!
8 0
3 years ago
A boy walks 6 km from a point P to a point Q on a bearing of 065. He then walks to a point R at a distance of 13 km on a bearing
Usimov [2.4K]

9514 1404 393

Answer:

  1. see below for a sketch
  2. 12 km

Step-by-step explanation:

The distance can be calculated using the Law of Cosines. The angle internal to the triangle at Q is (180°-(146° -65°)) = 99°. Then the distance PR can be found from ...

  PR² = PQ² +QR² -2·PQ·QR·cos(∠PQR)

  PR² = 6² +10² -2·6·10·cos(99°) ≈ 154.77

  PR ≈ √154.77 ≈ 12.44 . . . . km

The distance PR is about 12 km.

6 0
3 years ago
a student required to 40% marks to pass in exam he got 190 marks and fail with 10 marks. find total marks?
Andrej [43]

Answer:

500

Step-by-step explanation:

40%=190+10

40%=200

10%=50

100%=500

3 0
2 years ago
Find the volume of the cone
Sav [38]

Answer: 18.85 units^3

Step-by-step explanation:

V = 3.14 x r^2 x h/3

3 0
3 years ago
Read 2 more answers
Towers A and B are located 5 miles apart. A ranger spots a fire at a 42-degree angle from tower A. Another fire ranger spots the
lord [1]

Answer: The fire is 3.5 miles from tower B

Step-by-step explanation: Please refer to the attached diagram. The triangle in the attached diagram illustrates the clues given in the question. Both rangers are standing at points A and B respectively with a distance of 5 miles between them, which is line AB. Also, one ranger spots a fire from a tower at an angle of 42 degrees, which is point A. Another ranger spots the same fire from another tower, but from an angle of 64 degrees, which is point B. The fire is at point C on the triangle. Now we have a triangle with only one side known (5 miles) and three angles known (the third angle is computed as 180 - {64+42} which equals 74) which are 64 degrees, 42 degrees and 74 degrees.

The distance from the fire to tower B is calculated using the law of sines. (Note that this is not a right angled triangle, hence we cannot use trigonometric ratios). The law of sines is expressed as follows;

a/SinA = b/SinB or

a/SinA = c/SinC

Depending on the sides and angles we are given and the ones we are to calculate.

The distance from the fire to tower B is line BC, labeled as a in our diagram. Using the law of sines

a/SinA = c/SinC

(Note also that a is directly facing angle A, c is directly facing angle C, and so on)

a/SinA = c/SinC

a/Sin 42 = 5/Sin 74

By cross multiplication we now have

a (Sin 74) = 5 (Sin 42)

Divide both sides of the equation by Sin 74 and we now arrive at

a = 5 (Sin 42)/Sin 74

a = 5 (0.6691)/0.9613

a = 3.3455/0.9613

a = 3.4802

{rounded to the nearest tenth of a mile, a equals 3.5}

Therefore the distance from tower B to the fire is approximately 3.5 miles

3 0
3 years ago
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