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iogann1982 [59]
4 years ago
13

The function f(x)=5000(0.98)^0.3x

Mathematics
2 answers:
Paha777 [63]4 years ago
4 0
The answer is A.)
f(x)=5000(0.98)^0.3x   What is x=1 and x=5?

f(1)=5000(0.98)^0.3(1)       <<Plug in 1
 = 5000(0.98)^0.3              <<Multiply 1
 =5000(0.993957517)       <<mulitply 0.3 with 0.98
 =4969.78759                    <<mulitply the answer to ^^ with 5000
 =4970                               <<Round


f(5)=5000(0.98)^0.3(5)      <<plug in 5
 = 5000(0.98)^1.5              <<Mulitply 5
 =5000(0.970150504)      <<multiply 1.5 with 0.98
 =4850.75252                   <<muliply the answer to ^^ with 5000
 = 4851                              << round

Next, you do (y2 - y1)/(x2-x1)
 
(4970 - 4851)/(1 - 5)          <<plug in numbers (btw you get the 1 and 5 from                                                                                    plugging them in in the beginning)
=(119)/(4)                               <<Subtract 
 = -29.75                              << divide 

I hope this helps!!
Leona [35]4 years ago
3 0

Answer:

he is right

Step-by-step explanation:

↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓↓

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3 0
3 years ago
The function C(x) = 10x + 5,000 represents the cost to produce x number of items. How many items should be produced
mylen [45]

Answer:

The number of item should be more than to 100.

Step-by-step explanation:

Cost of x items = C(x) = 10x + 5000

Number of items = x

Average cost = \frac{Total \ cost \ of \ items}{Total \ number \ of \ items}

60>\frac{10x+5000}{x}

60x>10x+5000

50x>5000

x>\frac{5000}{50}

\therefore x>100

7 0
3 years ago
What's the distance between (6, 4) and (2, 1)
rodikova [14]

Answer:

5

Step-by-step explanation:

You will need the distance formula. d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}\\

(x_{1}, y_{1}) (x_{2}, y_{2})

Now plug in the two points into the distance formula.

d= \sqrt{(2-6)^{2}+(1-4)^{2} }

d= 5

3 0
3 years ago
Read 2 more answers
find the value of the polygon. the polygon has 6 interior angles 2 of them are y and 4 of them are (2Y-20)
Anna35 [415]
First we need to determine what the 6 angles must add to. Turns out we use this formula

S = 180(n-2)

where S is the sum of the angles (result of adding them all up) and n is the number of sides. In this case, n = 6. So let's plug that in to get

S = 180(n-2)
S = 180(6-2)
S = 180(4)
S = 720

The six angles, whatever they are individually, add to 720 degrees. The six angles are y, y, 2y-20, 2y-20,  2y-20,  2y-20, <span> 

They add up and must be equal to 720, so let's set up the equation to get...

(y)+(y)+(</span>2y-20)+(2y-20)+(2y-20)+(<span>2y-20) = 720

Let's solve for y

</span>y+y+2y-20+2y-20+2y-20+2y-20 = 720

10y-80 = 720

10y-80+80 = 720+80

<span>10y = 800
</span>
10y/10 = 800/10

y = 80

Now that we know the value of y, we can figure out the six angles

angle1 = y = 80 degrees
<span>angle2 = y = 80 degrees
</span><span>angle3 = 2y-20 = 2*80-20 = 140 degrees
</span>angle4 = 2y-20 = 2*80-20 =<span> 140 degrees
</span><span>angle5 = 2y-20 = 2*80-20 = 140 degrees
</span>angle6 = 2y-20 = 2*80-20 =<span> 140 degrees
</span>
and that's all there is to it
3 0
4 years ago
Images of 2 advancement angles
sergiy2304 [10]
I Gave You Your Pictures

4 0
3 years ago
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