What is 4,967 divided by 68 with a remainder no decimals
2 answers:
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AB^2 + BC^2 = AC^2
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117
Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9
Therefore AB is 9 cms.
AB^2 + 6^2 = square root 117^2
AB^2 + 36 = 117
Now subtract 117 from both sides
AB^2 = 81
AB = square root 81 = 9
Therefore AB is 9 cms.
Answer:
The mistake she made was ; She didn't change the sign when subtracting -3/4 from both sides
She wrote 5/4+3/4 instead of 5/4-3/4
Step-by-step explanation:
Correct solution:
Subtract-3/4 from both sides
Simplify