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EleoNora [17]
3 years ago
5

What’s the exact value of Cos(127.5)? Using trig identities like half angle and PLEASE EXPLAIN

Mathematics
1 answer:
vlada-n [284]3 years ago
8 0

Answer:

−0.608761429

Step-by-step explanation:

use the pathagreom theorem if you have two sides subtract that from 180

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(3×10^​2 ​​ )×(2×10^​−4 ​​ )= ​​
Alik [6]

Answer:

Step-by-step explanation:

First, lets simplify everything in the parenthesis.

(3×10^​2 ​​ )×(2×10^​−4 ​​ )= ​​

In the parenthesis, since exponents come before multiplication in the order of operations, we need to do the exponents first.

(3 • 100) • (2 • 1/10^4)

Now, we can just multiply everything from left to right to get:

6*10^-2

Or

.06

6 0
3 years ago
The manager of a bookstore uses the equation s = p - 3.5 to find the price a student pays for books
Bogdan [553]
The third one ???? why does the answe have to be 20 characters lone ajshsbwh
4 0
3 years ago
Read 2 more answers
You roll two six-sided dice. What is the probability that the sum is odd or a multiple of 5? Round your answer to the nearest te
liq [111]

Answer:

<em>The probability that the sum is odd or a multiple of 5</em>

<em>P(E₁∪E₂) = 0.58 = 58%</em>

Step-by-step explanation:

<u><em>Step ( i ) :-    </em></u>

<em>Given the two dice are thrown ,The total number of  exhaustive cases </em>

<em>n(S) =  6² = 36</em>

Let 'E₁' be the event of getting the sum is odd on two dice

E₁ = { (1,2)(1,4),(1,6),(2,1),(2,3),(2,5),(3,2)(3,4),(3,6),(4,1)(4,3),(4,5),(5,2),(5,4),(5,6),(6,1),(6,3),(6,5)}

n(E₁) = 18

Let 'E₂' be the event of getting the sum is multiple of 5 on two dice

E₂ = { (1,4),(2,3), (3,2),(4,1),(4,6),(5,5),(6,4)}  

n(E₂) = 7  

n(E₁∩E₂) = {(1,4),(2,3),(3,2),(4,1)} = 4

<u><em>Step(ii):-</em></u>

The probability that the event of getting the sum is odd on two dice

P(E_{1}) = \frac{n(E)}{n(S)} = \frac{18}{36}

The probability that the event of getting the sum is multiple of '5' on two dice

P(E_{2}) = \frac{n(E_{2} )}{n(S)} = \frac{7}{36}

The probability that the event of getting the sum is odd and multiple of '5' on two dice

P(E_{1} n E_{2}) = \frac{n(E_{1} n E_{2} )}{n(S)} = \frac{4}{36}

<em>The probability that the sum is odd or a multiple of 5</em>

<em>P(E₁∪E₂) = P(E₁) + p(E₂) - P(E₁ ∩ E₂)</em>

<em>               =    </em>\frac{18}{36} + \frac{7}{36} - \frac{4}{36}<em></em>

<em>               </em>\frac{18+7}{36} - \frac{4}{36} = \frac{25-4}{36} = \frac{21}{36}<em></em>

<em>P(E₁∪E₂) = 0.58 = 58%</em>

<u><em>Final answer</em></u><u>:-</u>

<em>The probability that the sum is odd or a multiple of 5</em>

<em>P(E₁∪E₂) = 0.58 = 58%</em>

<em></em>

4 0
3 years ago
The largest possible sum, less than 10, of two consecutive prime number is
Natali5045456 [20]

Answer:

8

Step-by-step explanation:

Primes below 10 are 1,2,3,5,7

the two consecutive primes that would add up less than 10 would be 3 and 5. 3+5 = 8

5 0
2 years ago
A girl needs help!!!!!
uysha [10]

Answer:

1. 17

2. 360

3. 6

Step-by-step explanation:

5 0
4 years ago
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