Ask question

Ask question

All categories

3 years ago

11

Graph the function I need 3 plots h(x) = - 3/5x +9

1 answer:

Alisiya [41]3 years ago

5 0

The function goes through (0,9) (6,5.4) and (15,0)

You might be interested in

Choose the unit that measures distance

Anna11 [10]

Answer:

Feet

Step-by-step explanation:

8 0

2 years ago

Please help me <br> I’ll mark brainiest

Lubov Fominskaja [6]

Answer:

which number

every of them?

8 0

2 years ago

Is the following irrational or rational?

prisoha [69]

6.4 is Rational. It ends in a decimal
if the nine is the last number and it does not go on (indicated by ...) then the number is rational
-2 is rational. It's an integer. All integers are rational.

4 0

2 years ago

Use polar coordinates to find the volume of the given solid. Inside both the cylinder x2 y2 = 1 and the ellipsoid 4x2 4y2 z2 = 6

Anton [14]

The Volume of the given solid using polar coordinate is: $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

V= $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

<h3>What is Volume of Solid in polar coordinates?</h3>

To find the volume in polar coordinates bounded above by a surface z=f(r,θ) over a region on the xy-plane, use a double integral in polar coordinates.

Consider the cylinder, $x^{2}+y^{2} =1$ and the ellipsoid, $4x^{2}+ 4y^{2} + z^{2} =64$

In polar coordinates, we know that

$x^{2}+y^{2} =r^{2}$

So, the ellipsoid gives

$4{(x^{2}+ y^{2)} + z^{2} =64$

4( $r^{2}$ ) + $z^{2}$ = 64

$z^{2}$ = 64- 4( $r^{2}$ )

z=± $\sqrt{64-4r^{2} }$

So, the volume of the solid is given by:

V= $\int\limits^{2\pi}_ 0 \int\limits^1_0{} \, [\sqrt{64-4r^{2} }- (-\sqrt{64-4r^{2} })] r dr d\theta$

= $2\int\limits^{2\pi}_ 0 \int\limits^1_0 \, r\sqrt{64-4r^{2} } r dr d\theta$

To solve the integral take, $64-4r^{2}$ = t

dt= -8rdr

rdr = $\frac{-1}{8} dt$

So, the integral $\int\ r\sqrt{64-4r^{2} } rdr$ become

= $\int\ \sqrt{t } \frac{-1}{8} dt$

= $\frac{-1}{12} t^{3/2}$

= $\frac{-1}{12} (64-4r^{2}) ^{3/2}$

so on applying the limit, the volume becomes

V= $2\int\limits^{2\pi}_ {0} \int\limits^1_0{} \, \frac{-1}{12} (64-4r^{2}) ^{3/2} d\theta$

= $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(64-4(1)^{2}) ^{3/2} \; -(64-4(2)^{0}) ^{3/2} ] d\theta$

V = $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

Since, further the integral isn't having any term of $\theta$ .

we will end here.

The Volume of the given solid using polar coordinate is: $\frac{-1}{6} \int\limits^{2\pi}_ {0} [(60) ^{3/2} \; -(64) ^{3/2} ] d\theta$

Learn more about Volume in polar coordinate here:

brainly.com/question/25172004

#SPJ4

3 0

1 year ago

Kevin is 3 years older than Daniel. Two years ago, Kevin was 4 times as old as Daniel

gogolik [260]

Answer:

kevin is 6 years old

Step-by-step explanation:

Let Kevin's age now be a

Daniel's age now be b

Kevin is 3 years older than Daniel. -> a-3 = b

Two years ago, Kevin was 4 times as old as Daniel -> a-2 = 4(b-2) = 4b -8

-> a-3 -(a-2) = b - (4b-8)

-> - 1 = -3 b +8

-> -9 = -3b

-> b = 3

-> a = 6

6 0

2 years ago

Read 2 more answers