Answer:
-14+77=63
21-82=-61
|-61|=61
So 63-61=2
Step-by-step explanation:
Answer:
1. cos(F) = 2. 5/13
tan (F) = 3. 12/5
sin (F) = 1. 12/13
2. Sin (R) = 1. 60/68 = 30/34 = 15/17
cos (R) = 2. 32/68 = 16/34 = 8/17
tan (R) = 3. 60/32 = 30/16 = 15/8
Step-by-step explanation:
1 picture:
sin = Opp/Hyp
cos = adj/hyp
tan = opp/adj
cos(F) = 2. 5/13
tan (F) = 3. 12/5
sin (F) = 1. 12/13
2 Picture:
Sin (R) = 1. 60/68 = 30/34 = 15/17
cos (R) = 2. 32/68 = 16/34 = 8/17
tan (R) = 3. 60/32 = 30/16 = 15/8
Answer:
4 ssquare units
Step-by-step explanation:
Answer:
Step-by-step explanation:
It is given that in △ABC, ∠ABC=90°, BH is an altitude and AB=9 and AC=12, thus using the Pythagoras theorem in △ABC, we get
Now, From ΔABC and ΔHBC, we have
∠ABC=∠BHC(each90)
∠ACB=∠HCB (Common)
By AA similarity, ΔABC is similar to ΔHBC.
Thus, using the similarity condition, we get
The size of chicken at the form would be 111.8 inches.
Step-by-step explanation:
Given that,
The average height of cow = x1 = 4 feet 5 inches
x1 = 4 x 12 + 5 = 53 inches (12 inches in a feet)
The average height of chicken = y1 = 13 inches.
The height of cow statue at form = x2 = 38 feet
x2 = 38 x 12 = 456 inches
The height of chicken statue = y2 = ?
For this, the ratio of height in both the scenarios would be the same. Therefore,
x1/y1 = x2/y2
now, by putting the values
53/13 = 456/y2
y2 = (456x 13) / 53
y2 = 111.8 inches
Hence, the size of chicken at the form would be 111.8 inches.
