Answer:
- Glycine
- Ribulose 1,5-bisphosphate
- 3-phosphoglycerate
- Glyceraldehyde 3-phosphate.
- Glucose
- Sucrose
Explanation:
The glycine, among other amino acids, helps to improve chlorophyll production and promotes the process of photosynthesis.
<u>Calvin cycle</u>
During the carbon fixation phase, a CO² molecule combinate with a ribulose 1,5-bisphosphate to form 6-carbonated molecules, which will divide into two 3-phosphoglycerate molecules.
During the reduction phase, NADPH donates its electrons to reduce 3-phosphoglycerate molecules, and turn them into glyceraldehyde 3-phosphate.
During the regeneration phase, a glyceraldehyde 3-phosphate molecule leaves the cycle and goes to the cytosol to form glucose. This step can be done when three CO² enter the cycle and produce six glyceraldehyde 3-phosphate molecules. One of them leaves the cycle to form glucose, while the other five are recycled.
<u>Cytosol: </u>
Once in the cytosol, glyceraldehyde 3-phosphate molecules are used to form glucose and fructose. These two molecules are the monosaccharides that form the sucrose.
Once sucrose is formed, it is transported from the photosynthetic tissues to different parts of the plant by the phloem.
Answer:
D. Meiosis forms four cells all with different genetic material
Explanation:
They are haploid cells and each cell only had one set of chromosomes. Meiosis results in variation.
Answer:
30% Thymine
Explanation:
If 30% of Adenine is present, it would be reasonable to assume that 30% of Thymine will be present, as the ratio between the two complementary nitrogenous bases will be roughly equal.
Therefore, that leaves us with 40% between Cytosine and Guanine. Since the ratio between them would be equal, it gives us 20% of Cytosine and 20% of Guanine.
<u>Therefore:</u>
30% of A + 30% of T + 20% of C + 20% of G = 100% DNA
Answer:
-3
Explanation:
because when you do this math solution you get -3
