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Kay [80]
3 years ago
15

How much does the atmosphere weigh over each square meter of surface? express this in tonnes (units of 1000 kg). recall the conv

ersion factors: 104 cm2 = 1m2, 1 tonne = 1000 kg = 106
g.
Mathematics
1 answer:
Anettt [7]3 years ago
7 0
Atmospheric pressure = 101,325 Newtons / m²
Weight per meter square = 101,325 Newtons
Mass per meter square = 101,325 / (9.81 x 1000)
Mass per meter square = 10.3 tonnes per m²
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William scored 24.5 points out of 30 on his math assignment. His teacher subtracted 5 points for being late. How many points is
Svetradugi [14.3K]

Answer:

William was 0.5 points away from a perfect score.

Step-by-step explanation:

If the teacher didn't subtract 5 points, he would have 24.5 + 5 = 29.5 points.

30 - 29.5 = 0.5

William was 0.5 points away from a perfect score.

8 0
3 years ago
Pls help me with my homework
timofeeve [1]
Yes I worked it in my brain hahahahahah
4 0
2 years ago
Help please and thanks! I always give brainliest! (Explain too please)
qwelly [4]

Answer:

A. 2/3

Opposite Sides of a Parallelogram

The two pairs of sides in a parallelogram are parallel to each other.

Parallel lines have the same slope.

The slope of the opposite sides of a parallelogram are congruent (equal in measure).

Given:

Slope of PQ = 2/3

Slope of QR = -1/2

For PQRS to be a parallelogram, the slope of SR must be same as the slope of PQ.

This implies that: Slope of SR = Slope of PQ = 2/3.

Therefore, based on the properties of a parallelogram, the slope of SR for PQRS to be a parallelogram would be: 2/3.

4 0
2 years ago
Find the equation of a circle with a center at (7,2) and a point on the circle at (2,5)?
monitta

Answer:

(x-7)^2+(y-2)^2=34

Step-by-step explanation:

We want to find the equation of a circle with a center at (7, 2) and a point on the circle at (2, 5).

First, recall that the equation of a circle is given by:

(x-h)^2+(y-k)^2=r^2

Where (<em>h, k</em>) is the center and <em>r</em> is the radius.

Since our center is at (7, 2), <em>h</em> = 7 and <em>k</em> = 2. Substitute:

(x-7)^2+(y-2)^2=r^2

Next, the since a point on the circle is (2, 5), <em>y</em> = 5 when <em>x</em> = 2. Substitute:

(2-7)^2+(5-2)^2=r^2

Solve for <em>r: </em>

<em />(-5)^2+(3)^2=r^2<em />

Simplify. Thus:

25+9=r^2

Finally, add:

r^2=34

We don't need to take the square root of both sides, as we will have the square it again anyways.

Therefore, our equation is:

(x-7)^2+(y-2)^2=34

4 0
2 years ago
A picture has a height that is 2 times it’s width . It is to be enlarged to an area of 128 in 2
morpeh [17]

9514 1404 393

Answer:

  8 in by 16 in

Step-by-step explanation:

In your equation, we presume that x represents the width. Solving for x, we have ...

  2x² = 128 . . . . . . given equation

  x² = 64 . . . . . . . . divide by 2

  x = √64 = 8 . . . . square root

The enlargement will be 8 inches by 16 inches.

8 0
2 years ago
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