It would be 1n - 12 + 8y.
4n - 3n = 1n
12 + 8y don’t mix so we can leave it.
Therefore: 1n - 12 + 8y
The coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
<h3>What are the coordinates of the vertices of the image?</h3>
The vertices of the preimage of the triangle are given as:
L = (4, -6)
M = (5, -1)
N = (7, -3)
The rotation is given as: 180 degrees counterclockwise
<h3 />
The rule of this rotation is
(x, y) => (-x, -y)
So, we have:
L' = (-4, 6)
M' = (-5, 1)
N' = (-7, 3)
Hence, the coordinates of the vertices of the image are L' = (-4, 6), M' = (-5, 1) and N' = (-7, 3)
Read more about rotation at:
brainly.com/question/4289712
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<span>If two numbers on a graph differ by 1, without scale, the amount of inequality could vary infinitely. If the scale is 2, a difference of 1 is half the scale amount, but if the scale is 1000, the difference may be negligible. It is the scale that shows the degree to which the entries differ.</span>
Answer:
114°
Step-by-step explanation:
The exterior angle is the sum of the remote interior angles.
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<h3>setup</h3>
(11x +15)° = 60° +6x°
<h3>solution</h3>
5x = 45 . . . . . . . . . divide by °, subtract 15+6x
x = 9 . . . . . . . . . . divide by 5
The measure of exterior angle KMN is ...
m∠KMN = (11(9) +15)° = 114°
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<em>Additional comment</em>
Both the sum of interior angles and the sum of angles of a linear pair are 180°. If M represents the interior angle at vertex M, then we have ...
60° +6x° +M = 180°
(11x +15)° +M = 180°
Equating these expressions for 180° and subtracting M gives the relation we used above:
(11x +15)° +M = 60° +6x° +M . . . . . equate the two expressions for 180°
(11x +15)° = 60° +6x° . . . . . . . . . . . subtract M
This is also described by "supplements to the same angle are equal."
If there is 290 kids,14 teachers, and 5 subs the you have to do adding
There is 309 kids with teachers and subs! Hope it 209 helps! Happy Halloween!!!
14
<u>+ 5
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