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3 years ago

WITH PICTURE!!3. What is the value of x in the regular polygon below? (3 points)

Mathematics

1 answer:

monitta3 years ago

8 0

Answer: FIRST OPTION.

Step-by-step explanation:

Regular polygons are those polygons whose sides are equal in length and whose angles are all equal.

By definition each interior angle of a Regular polygon,is:

$\frac{180 ( n -2 )}{n}$ (In degrees)

Where "n" is the number of sides of the polygon.

Observe the Regular polygon given in the exercise.

Since it has 6 sides, you can conclude that it is an Hexagon. Then:

$n=6$

Substituting into $\frac{180 ( n -2 )}{n}$ and evaluating, you get:

$\frac{180 ( 6 -2 )}{6}=120\°$

Knowing this, you can write the following equation:

$3x=120$

Finally, you must solve for "x" in order to find its value. This is:

$x=\frac{120}{3}\\\\x=40$

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Trisha and Byron are washing and vacuuming cars to raise money for a class trip. Trisha raised $38 washington 5 cars and vacuumi

ANEK [815]

Answer:

They charged $6 for washing and $2 for vacuuming the car.

Step-by-step explanation:

Let the charge of washing a car be 'x'.

And also let the charge of vacuuming a car be 'y'.

Now according to question, Trisha raised $38 washing 5 cars and vacuuming 4 cars.

So framing the above sentence in equation form, we get;

$5x+4y=38\ \ \ \ \ equation\ 1$

Again according to question, Byron raises $28 by washing 4 cars and vacuuming 2 cars.

So framing the above sentence in equation form, we get;

$4x+2y=28\ \ \ \ \ equation\2$

Now multiplying equation 2 by '2', we get;

$2(4x+2y)=28\times2\\\\8x+4y=56\ \ \ \ equation\ 3$

Now we subtract equation 1 from equation 3 and get;

$(8x+4y)-(5x+4y)=56-38\\\\8x+4y-5x-4y=18\\\\3x=18\\\\x=\frac{18}{3}=6$

Now substituting the value of 'x' in equation 1, we get;

$5x+4y=38\\\\5\times6+4y=38\\\\30+4y=38\\\\4y=38-30=8\\\\y=\frac{8}{4}=2$

Hence They charged $6 for washing and $2 for vacuuming the car.

8 0

3 years ago

Answer this pls..................

Sindrei [870]

Answer:

so we know:

total of 20 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

1 2 3 4 5 6 7 8

3 are in all of them

1 2 3

1) underline the main 3

total of 20 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry has a total of 14 students

1 2 3 4 5 6 7 8 9 10 11 12 13 14

8 students are in physics

1 2 3 4 5 6 7 8

2) lets bold the physics students, if you are in physics you have to do chem so that means 8 of the chem students also take physics.

total

1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 9 10 11 12 13 14

physics

1 2 3 4 5 6 7 8

3) now we bring biology into the "equation"

off the bat we know 3 are definitely in Biology.

so if 4 study ONLY biology we can cross them off our list see the {}

total

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3 

4) so we have a total of 20 students, 3 in all of the classes (underlined), 8 in physics (bolded). If there 14 in chemistry, 4 take ONLY chemistry {}, 8 take chemistry as well (bolded), that leaves two students, so they must belong in biology. lets italicise them.

total

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3  13 14

5) out of our total of 20 students we know 14 of the students classes, so the remaining six must be in biology.

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3 13 14 15 16 17 18 19 20

6) so that was our "diagram" so now lets count how many are in chemistry and biology but NOT physics.

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

-1 2 3 4 5 6 7 8- {9 10 11 12} 13 14

physics

-1 2 3 4 5 6 7 8-

biology

-1 2 3 -13 14 15 16 17 18 19 20

there are 14 students in chemistry and 11 in biology, 5 of them are in both classes so 14-5= 9 and 11-5= 6 9+6=16. BUT 8 of those sixteen are also in -physics- so we arent counting them, we put those students in dashes. so lets count the students out of the dashes. so twelve of them are in chemistry and biology but not physics.

7) so how many are in just biology but not the other classes? lets look at the graph.

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14 15 16 17 18 19 20

chemistry

1 2 3 4 5 6 7 8 {9 10 11 12} 13 14

physics

1 2 3 4 5 6 7 8

biology

1 2 3 13 14 15 16 17 18 19 20

in the class of biology students 1 2 3 13 and 14 take other classes that leaves students 15 16 17 18 19 and 20. so 6 students take ONLY biology.

sorry its long but i hope this helps!

3 0

3 years ago