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3 years ago

Find the missing length. If needed, round to the nearest tenth.

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

4 0

Answer:

Step-by-step explanation:

Line DE is parallel to line AG.

Also, triangle ABG is similar to triangle to triangle DBE.

Therefore,

AB/DB = GB/EB = AG/DE

AB = 5 + 6 = 11

GB = 9 + x

Therefore,

11/6 = (9 + x)/9

Cross multiplying, it becomes

11 × 9 = 6(9 + x)

99 = 54 + 6x

Subtracting 54 from the Left hand side and the right hand side of the equation, it becomes

54 - 54 + 6x = 99 - 54

6x = 45

Dividing the Left hand side and the right hand side of the equation by 6, it becomes

6x/6 = 45/6

x = 7.5

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Answer:

ans is (D)500/3 π unit^3

Explanation :

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3 years ago

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Answer:

Step-by-step explanation:

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2 years ago

An elevator starts on the 100th floor. It descends 4 floors every 10 seconds. At what floor will the elevator be 60 seconds afte

Artyom0805 [142]

So is 4 floors / 10 seconds
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3 years ago

Read 2 more answers

Find the dot product of the position vectors whose terminal points are (14, 9) and (3, 6).

erma4kov [3.2K]

Answer:

Step-by-step explanation:

The formula for the dot product of vectors is

u·v = |u||v|cosθ

where |u| and |v| are the magnitudes (lengths) of the vectors. The formula for that is the same as Pythagorean's Theorem.

$|u|=\sqrt{14^2+9^2}$ which is $\sqrt{277}$

$|v|=\sqrt{3^2+6^2}$ which is $\sqrt{45}$

I am assuming by looking at the above that you can determine where the numbers under the square root signs came from. It's pretty apparent.

We also need the angle, which of course has its own formula.

$cos\theta=\frac{uv}{|u||v|}$ where uv has ITS own formula:

uv = (14 * 3) + (9 * 6) which is taking the numbers in the i positions in the first set of parenthesis and adding their product to the product of the numbers in the j positions.

uv = 96.

To get the denominator, multiply the lengths of the vectors together. Then take the inverse cosine of the whole mess:

$cos^{-1}\theta=\frac{96}{111.64676}$ which returns an angle measure of 30.7. Plugging that all into the dot product formula: