The mass of oxygen that is required to react completely with 2 moles of CH4 is 128 grams
calculation
mass = moles xmolar mass
The molar mass of O2= 16 x2 = 32 g/mol
find the number of moles
first write the the equation for reaction
CH4 + 2O2 → CO2 + 2H2O
the mole ratio between CH4 to O2 is 1:2 therefore the moles of O2 = 2 x2 = 4 moles
mass is therefore = 32 g/mol x 4 moles = 128 grams
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Answer:
See explanation
Explanation:
Biology- digestion of food materials
Chemistry- dissolving salt in water
Astronomy - observing day and night
Physics - watching a television
Geography - observing weather changes during the day
Answer: A. 1.0 gallon of water
Explanation: to calculate the mass of each option, we have to note the unit conversations, and for the purposes of this question we will be using the density of the substance that is not under the condition of temperature or pressure, because we have option B which conditions of pressure and temperature are not stated.
For option A:
1gallon= 3.7854liters
Density= 1.0g/ml= 1000g/liters
mass= volume×Density
Therefore
Mass= 3.7854×1000= 3785gram
For option B:
5lb potatoes 1kg=2.2046lb
Therefore:
(5lb×1kg)/2.2046lb= 2.26798kg
Where 1kg=1000gram
(2.26798kg×1000g)/1kg= 2268grams
For option C:
1gallon=3.7854liters
Density=0.8g/ml= 800g/l
Therefore:
Mass= density×volume
Mass=800×3.7854=3028grams
For option D:
Mass= density×volume
Density= 800g/ml
Volume=3liters
Therefore mass=
800×3=2400grams
THEREFORE FROM THE OPTIONS ABOVE WE CAN SEE THAT OPTION A OF 1 GALLON OF WATER, HAS THE LARGEST MASS, WITH 3785grams