Answer:
Weight of boulder = 22,400 gram
Explanation:
Given:
Volume = 8,000 cm³
Density = 2.8
Find:
Weight of boulder
Computation:
Weight of boulder = Volume x Density
Weight of boulder = 8,000 x 2.8
Weight of boulder = 22,400 gram
Answer:
False.
Explanation:
I am not completely sure, but I don't believe the earth is getting larger.
Sodium reacts with chlorine to form Na+ ions and Cl- ions in spite of the fact that the first ionization energy of sodium is larger than the electron affinity of chlorine. To explain this, we need to divide the reaction between sodium and chlorine
<u>Answer:</u> The volume of oxygen gas at STP is 446 mL
<u>Explanation:</u>
STP conditions are:
Pressure of the gas = 1 atm
Temperature of the gas = 273 K
To calculate the volume when temperature and pressure has changed, we use the equation given by combined gas law. The equation follows:
where,
are the initial pressure, volume and temperature of the gas
are the final pressure, volume and temperature of the gas
We are given:
Putting values in above equation, we get:
Hence, the volume of oxygen gas at STP is 446 mL
Answer:
28.0mL of the 0.0500M NaOH solution
Explanation:
<em>0.126g of lactic acid diluted to 250mL. Titrated with 0.0500M NaOH solution.</em>
<em />
The reaction of lactic acid, H₃C-CH(OH)-COOH (Molar mass: 90.08g/mol) with NaOH is:
H₃C-CH(OH)-COOH + NaOH → H₃C-CH(OH)-COO⁻ + Na⁺ + H₂O
<em>Where 1 mole of the acid reacts per mole of the base.</em>
<em />
You must know the student will reach equivalence point when moles of lactic acid = moles NaOH.
the student will titrate the 0.126g of H₃C-CH(OH)-COOH. In moles (Using molar mass) are:
0.126g ₓ (1mol / 90.08g) = <em>1.40x10⁻³ moles of H₃C-CH(OH)-COOH</em>
To reach equivalence point, the student must add 1.40x10⁻³ moles of NaOH. These moles comes from:
1.40x10⁻³ moles of NaOH ₓ (1L / 0.0500moles NaOH) = 0.0280L of the 0.0500M NaOH =
<h3>28.0mL of the 0.0500M NaOH solution</h3>
