He should have subtracted the discount and added the sales tax
<span>5ab^2 + 10ab
5ab^2 = 5ab *(b)
10ab = 5ab *(2)
so GCF of </span>5ab^2 + 10ab = 5ab
(1) y² + x² = 53
(2) y - x = 5 ⇒ y = x + 5
subtitute (2) to (1)
(x + 5)² + x² = 53 |use (a + b)² = a² + 2ab + b²
x² + 2x·5 + 5² + x² = 53
2x² + 10x + 25 = 53 |subtract 53 from both sides
2x² + 10x - 28 =0 |divide both sides by 2
x² + 5x - 14 = 0
x² - 2x+ 7x - 14 = 0
x(x - 2) + 7(x - 2) = 0
(x - 2)(x + 7) = 0 ⇔ x - 2 = 0 or x + 7 = 0 ⇔ x = 2 or x = -7
subtitute the values of y to (2)
for x = 2, y = 5 + 2 = 7
for x = -7, y = 5 + (-7) = 5 - 2 = 3
Answer: x = 2 and y = 7 or x = -7 and y = 3
Answer:
11) Here given Function,

And, 
For f(x) = g(x)






When we solve this equation,
We found,
x = 12.5227 ≈ 12.53
Thus, the required solution is, x = 12.53
12) Here the height of rocket A in x second,

And, The height gain by the rocket B in x seconds,

If at x seconds both A and B gain the same height,
That is, f(x) = g(x)
⇒ 
⇒
⇒ 
⇒ 
⇒ x = 1.125 ≈ 1.13
Thus, the required solution is x = 1.13 seconds (approx)