Answer: No, x+3 is not a factor of 2x^2-2x-12
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Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
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Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
540ml with 12% solution
get 12% of 540
540 times 0.12 = 64.8 ml of pure acid
For ex:
U have 4/8 - 6/2 u would probably have to use KCF- Keep Change Flip
So then it’ll be 4/8 + 2/6
U kept the 4/8 then u changed the subtraction to addition and u flipped the 2 to the numerator and the 6 denominator.
Idk my dude this is what I can think of
Answer:
C(t) = $28,000(0.811)^t (Answer A)
Step-by-step explanation:
The value of the car is decreasing. Thus, by the end of the first year of ownership, the car will have the value $28,000(1 -0.189)^1, where the "-0.189" represents DECAY instead of GROWTH.
Please use " ^ " to indicate exponentiation.
Then the desired formula is C(t) = $28,000(0.811)^t (Answer A)
